Eldorian said:
What are you, a statistician? Only a statistician can take simple probability calculations and use some oddly named model to entirely mess it up. The OP's reasoning is perfect. I'd have given him an A. In fact, his reasoning is better than yours, because yours requires you to use the fact that men before you used the OP's reasoning and created this random variable.
PS:
<--- mathematician.
Ehy, Mr. Funny, I am a mathematician.
But since you are smarter than me, you can explain this:
1) We're interested in the number of failures before reaching a fixed number of successes.
2) The experiment consists of a sequence of independent trials.
3) The probability of success, p, is constant from one trial to another.
We want the probability of x failures before a number of successes r.
This is (Polya/Pascal/negative binomial distribution):
P(X=x|r,p)=OVER(x+r-1, r-1)*p^r*(1-p)^x
For the most basic skill challenge outlined above, x=2, r=4, p=0.55
If you do the math (you are a mathematician, right?), then you get something like:
P(X=2|4,0.55)=0.1240
So, there is only a 12% chance of 2 failures before 4 successes.
Clearly, this result is quite different from what the OP got.
Now, since you are the smarter here, you can either disprove me, or the other guy. I am fine in either case.
Thanks,
EDIT: Oh, obviously one might want the cumulative probability, so:
P(X<=2|4, 0.55)=P(X=0)+P(X=1)+P(X=2)=0.2552
So, the probability of getting AT MOST 2 failures is 0.26