Spontaneous Paladin/Ranger? (UA style)

[fba827]

No, I don't have one designed yet to share. Before I started on this endeavour, I thought I would ask ...

using what UA did as an option for making spontaneous clerics and druids, anyone come up with something similar for making spontaneous casting paladins and rangers?


I was going to, simply haven't sat down and given it any thought yet. Thought I'd see if there were any good ideas before I started that little diversion ...

Thoughts? Comments?

(and to keep the question from coming up, let's just presume that I want a paladin and ranger to be able to cast divine spells regardless of what some varients out there are.. -- I just want them to be able to do it spontaneously)

 

[Li Shenron]

The UA method to make a divine caster spontaneous is based on the Sorcerer known spells per level. Since divine casters "know" all the spells from their list, they have to give up that in exchange for the spontaneity.

There is no spontaneous caster with a spell list made by spells of level 1-4 to compare against, but you can try to estrapolate a table of known spells per level from either the Bard or the Sorcerer table.

If you read such table "vertically", that is by column, you notice that a Bard knows spells of every level with a progression like 2 3 3 4 4 4 4 4 4 4 4 4 4 5 5 ... 5 while a Sorcerer is slightly more complicated, and for example levels 3 and 4 follow a progression like 1 2 2 3 3 4 4 ... 4 (while levels 1 and 2 go up to 5).

You could try the same vertical progression for a Paladin/Ranger, starting that column as soon as the Pal/Ran gets access to that level of spell. Here's the result:

[B]Level________spells/day______known(Brd)______known(Sor)[/B]
1st           -  -  -  -
2nd           -  -  -  -
3rd           -  -  -  -
4th           0  -  -  -        2                   1
5th           0  -  -  -        3                   2
6th           1  -  -  -        3                   2
7th           1  -  -  -        4                   3
8th           1  0  -  -        4  2                3  1
9th           1  0  -  -        4  3                4  2
10th          1  1  -  -        4  3                4  2
11th          1  1  0  -        4  4  2             5  3  1
12th          1  1  1  -        4  4  3             5  3  2
13th          1  1  1  -        4  4  3             5  4  2
14th          2  1  1  0        4  4  4  2          5  4  3  1
15th          2  1  1  1        4  4  4  3          5  5  3  2
16th          2  2  1  1        4  4  4  3          5  5  4  2
17th          2  2  2  1        5  4  4  4          5  5  4  3
18th          3  2  2  1        5  4  4  4          5  5  4  3
19th          3  3  3  2        5  4  4  4          5  5  4  4
20th          3  3  3  3        5  4  4  4          5  5  4  4

As you see, with the Sor progression he has basically always 1 less spell of the highest levels and sometimes 1 more of the lowest levels. This is just an idea that you may take as a starting point and then calculate more accurate numbers.