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MotW: Tempest question: 2H vs 2W, again!
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<blockquote data-quote="Gaiden" data-source="post: 59338" data-attributes="member: 103"><p>The answer to the original question, is all else being equal, the tempest that has no penalty to hit while wielding two weapons is better than the other warrior holding any weapon two handed.</p><p></p><p>The extra damage from str now is not statistically diminished.</p><p></p><p>Eg.</p><p></p><p>THF - base dmg for twohanded sword = 2d6, +1.5X for str +Y for other benefits.</p><p></p><p>TWF - base dmg for doublesword = (2x1d8, +1.5X for str +2xY for other benefits)</p><p></p><p>Consider 10th level tempest (20th level character): +20/+20/+15/+15/+10/+10/+5/+5</p><p></p><p>vs.</p><p></p><p>2hf</p><p>+20/+15/+10/+5</p><p></p><p>AC = Z</p><p></p><p>Assume statistical average for attack rolls</p><p></p><p>TWF</p><p></p><p>((10.5(avgd20 roll)+A (for benefits)+20 (for bab))-Z(for AC))(4.5+X+Y)+((10.5(avgd20 roll)+A (for benefits)+15 (for bab))-Z(for AC))(4.5+X+Y)+((10.5(avgd20 roll)+A (for benefits)+10 (for bab))-Z(for AC))(4.5+X+Y)+((10.5(avgd20 roll)+A (for benefits)+5 (for bab))-Z(for AC))(4.5+X+Y)+((10.5(avgd20 roll)+A (for benefits)+20 (for bab))-Z(for AC))(4.5+.5X+Y)+((10.5(avgd20 roll)+A (for benefits)+15 (for bab))-Z(for AC))(4.5+.5X+Y)+((10.5(avgd20 roll)+A (for benefits)+10 (for bab))-Z(for AC))(4.5+.5X+Y)+((10.5(avgd20 roll)+A (for benefits)+5 (for bab))-Z(for AC))(4.5+.5X+Y)</p><p></p><p>That = 828+36A+138X+6AX+184Y+8AY-(36Z+6ZX+8ZY)</p><p></p><p>Going through a similar process for 2hf yields</p><p></p><p>644+28A+138X+6AX+92Y+4AY-(28Z+6ZX+4ZY)</p><p></p><p>For simplification between comparisons, the 138X, 6AX and 6ZX can be eliminated from the equation. Therefore, if the second equation subtracted from the first yields a positive number twf is better.</p><p></p><p>184+8A+92Y+4AY-(8Z+4ZY) is our end result.</p><p></p><p>Remeber we are assuming all else is equal between the two except one is using two weapons and the other one.</p><p></p><p>Rearrange the following equation:</p><p></p><p>184+92Y+4(2A+AY)-4(2Z+ZY)</p><p></p><p>Obviously, if A=Z twf is better, alot better. Remember A is the benefit to hit and Z is the armor class (Y is always positive). Only when Z is 92 points higher than A is twoweapon fighting better.</p><p></p><p>WHen is that going to happen - practically never.</p><p></p><p>I haven't even included criticals in this calculation which will only further help twf.</p></blockquote><p></p>
[QUOTE="Gaiden, post: 59338, member: 103"] The answer to the original question, is all else being equal, the tempest that has no penalty to hit while wielding two weapons is better than the other warrior holding any weapon two handed. The extra damage from str now is not statistically diminished. Eg. THF - base dmg for twohanded sword = 2d6, +1.5X for str +Y for other benefits. TWF - base dmg for doublesword = (2x1d8, +1.5X for str +2xY for other benefits) Consider 10th level tempest (20th level character): +20/+20/+15/+15/+10/+10/+5/+5 vs. 2hf +20/+15/+10/+5 AC = Z Assume statistical average for attack rolls TWF ((10.5(avgd20 roll)+A (for benefits)+20 (for bab))-Z(for AC))(4.5+X+Y)+((10.5(avgd20 roll)+A (for benefits)+15 (for bab))-Z(for AC))(4.5+X+Y)+((10.5(avgd20 roll)+A (for benefits)+10 (for bab))-Z(for AC))(4.5+X+Y)+((10.5(avgd20 roll)+A (for benefits)+5 (for bab))-Z(for AC))(4.5+X+Y)+((10.5(avgd20 roll)+A (for benefits)+20 (for bab))-Z(for AC))(4.5+.5X+Y)+((10.5(avgd20 roll)+A (for benefits)+15 (for bab))-Z(for AC))(4.5+.5X+Y)+((10.5(avgd20 roll)+A (for benefits)+10 (for bab))-Z(for AC))(4.5+.5X+Y)+((10.5(avgd20 roll)+A (for benefits)+5 (for bab))-Z(for AC))(4.5+.5X+Y) That = 828+36A+138X+6AX+184Y+8AY-(36Z+6ZX+8ZY) Going through a similar process for 2hf yields 644+28A+138X+6AX+92Y+4AY-(28Z+6ZX+4ZY) For simplification between comparisons, the 138X, 6AX and 6ZX can be eliminated from the equation. Therefore, if the second equation subtracted from the first yields a positive number twf is better. 184+8A+92Y+4AY-(8Z+4ZY) is our end result. Remeber we are assuming all else is equal between the two except one is using two weapons and the other one. Rearrange the following equation: 184+92Y+4(2A+AY)-4(2Z+ZY) Obviously, if A=Z twf is better, alot better. Remember A is the benefit to hit and Z is the armor class (Y is always positive). Only when Z is 92 points higher than A is twoweapon fighting better. WHen is that going to happen - practically never. I haven't even included criticals in this calculation which will only further help twf. [/QUOTE]
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