Let's examine the numbers in rolling two d20's in the advantage case. A success is when one or both of the d20 rolls are a success.
Let p = probability of success of a single d20 roll.
Let P2 = probability both or one of d20 rolls are a success.
The probability of the two d20's being failures = (1-p)^2
Probably of rolling a success P2 = 1 - (1-p)^2 = 2 p - p^2
Plugging in some numbers:
p = 0.95, P2 = 0.9975
p = 0.90, P2 = 0.99
p = 0.85, P2 = 0.9775
p = 0.80, P2 = 0.96
p = 0.75, P2 = 0.9375
p = 0.70, P2 = 0.91
p = 0.65, P2 = 0.8775
p = 0.60, P2 = 0.84
p = 0.55, P2 = 0.7975
p = 0.50, P2 = 0.75
p = 0.45, P2 = 0.6975
p = 0.40, P2 = 0.64
p = 0.35, P2 = 0.5775
p = 0.30, P2 = 0.51
p = 0.25, P2 = 0.4375
p = 0.20, P2 = 0.36
p = 0.15, P2 = 0.2775
p = 0.10, P2 = 0.19
p = 0.05, P2 = 0.0975
In the disadvantage case, the probability of a successful roll is when both d20's are a success is p^2. (p is the probability of rolling a success on one d20).
Plugging in numbers.
p = 0.95, p^2 = 0.9025
p = 0.90, p^2 = 0.81
p = 0.85, p^2 = 0.7225
p = 0.80, p^2 = 0.64
p = 0.75, p^2 = 0.5625
p = 0.70, p^2 = 0.49
p = 0.65, p^2 = 0.4225
p = 0.60, p^2 = 0.36
p = 0.55, p^2 = 0.3025
p = 0.50, p^2 = 0.25
p = 0.45, p^2 = 0.2025
p = 0.40, p^2 = 0.16
p = 0.35, p^2 = 0.1225
p = 0.30, p^2 = 0.09
p = 0.25, p^2 = 0.0625
p = 0.20, p^2 = 0.04
p = 0.15, p^2 = 0.0225
p = 0.10, p^2 = 0.01
p = 0.05, p^2 = 0.0025