I could do that, but I don't think it'd be right.JVisgaitis said:180 lbs. Just take 90% of his weight.
JVisgaitis said:180 lbs. Just take 90% of his weight.
LightPhoenix said:Actually, by that metric, you'd want 10%, or 20lbs.
BUT,
You may have a relative height, weight, and depth reduction of 90% each way, but that actually reduces volume to 10%*10%*10%, or 0.1%. So, density staying the same, and therefore since weight (by mass) is proportional to volume, the actual weight would be [EDIT Ugh Math] 0.1% of 200lbs, or 0.2 lbs.
JQP said:A=B( X * Y * Z)
where
A=new weight
B=original weight
X=new dimensional scale
Y=new dimensional scale
Z=new dimensional scale
?