Agamon
Adventurer
So, I was checking what the encounters that it looks the party will come up against tonight for my game. This paragraph, from the DM Basic rules is worded slightly wrong, I think:
By the wording, you multiply the xp of the entire encounter according to how many creatures are in the entire encounter. That's fine if all the monsters are the same, but it's a bit messed up if you have different monsters in the same encounter.
For example, a CR 3 (700 xp) creature is an average encounter for 4 3rd level PCs. Add 2 CR 0 (10 xp) creatures, and it becomes deadly (1440 xp). That's absurd.
So I think the intention is that you multiply each group of different creatures in the encounter, and then add that together after to get the actual difficulty of the encounter. So above, we have 700 + (10 x2 x1.5) = 730 xp.
That sound right to everyone else?
3. Adjust Encounter XP Value Based on the Number of Monsters. Based on the number of monsters in the encounter, multiply the encounter’s XP value by the matching multiplier from the Encounter XP Multipliers table. Thus, if you have an encounter with 4 monsters in it, multiply the total XP value of the encounter by 2 for the purposes of determining how difficult the encounter is. This doesn’t change the actual XP award the adventurers receive for overcoming the monsters, just your calculations of how difficult the encounter is.
By the wording, you multiply the xp of the entire encounter according to how many creatures are in the entire encounter. That's fine if all the monsters are the same, but it's a bit messed up if you have different monsters in the same encounter.
For example, a CR 3 (700 xp) creature is an average encounter for 4 3rd level PCs. Add 2 CR 0 (10 xp) creatures, and it becomes deadly (1440 xp). That's absurd.
So I think the intention is that you multiply each group of different creatures in the encounter, and then add that together after to get the actual difficulty of the encounter. So above, we have 700 + (10 x2 x1.5) = 730 xp.
That sound right to everyone else?