Because members of a group can be surprised even if the other members aren’t, you'll determine which player is surprised and which one isn't (P2 & P3 for exemple haven't notice a threat) and then run the 1st round accordingly.I have a question about surprise round with multiple targets.
Exemple: enemies in different locations trying to surprise players.
Stealth test:
enemy 1 = 17
enemy 2 = 14
enemy 3 = 8
Passive perception:
Player 1 = 18
Player 2 = 15
Player 3 =9
So, player 1 perceive every enemy, player 2 was surprised by 1 enemy and player 3 for 2. How surprise round will work in that case?
Because members of a group can be surprised even if the other members aren’t, you'll determine which player is surprised and which one isn't (P2 & P3 for exemple haven't notice a threat) and then run the 1st round accordingly.
Surprise: A member of a group can be surprised even if the other members aren’t.
Jeremy Crawford wrote in a recent Sage Advice: "You can be surprised even if your companions aren’t, and you aren’t surprised if even one of your foes fails to catch you unawares." http://dnd.wizards.com/articles/features/rules-answers-november-2015Yes that part I know. But they notice enemy 3, so they can act against enemy 3? Enemy 3 will not act? Player 2 and 3 can't act but they don't grant advantage against enemy 3 and can use reaction in it?
Jeremy Crawford wrote in a recent Sage Advice: "You can be surprised even if your companions aren’t, and you aren’t surprised if even one of your foes fails to catch you unawares." http://dnd.wizards.com/articles/features/rules-answers-november-2015
So in your exemple no PCs would be surprised because each one at least notice 1 threat who failed to catch him unaware.
This doesn't looks right to me. So if 10 enemies try stealth check and only 1 pass, the entire group will be surprised even if the other 9 failed?