So I’m preparing to DM Desert of Desolation (adapted for 5e) but I’m confused by the exploration random encounters.
Chapter 5 p. 19 says:
“While the PCs are in this area, roll 1d6 every turn. On a roll of 1, there will be a random encounter.”
My understanding is that in the edition this adventure was written, a “turn” corresponds to ten minutes.
Looking at the map, the players will need to traverse about 50 hexes. On page 8 it says it will take the players approximately 3.5 hours to cross each hex.
This means there will be 3.5 * 6 * 50 = 1050 random encounter dice rolls to cross this area. What am I missing?
Thanks for your help!
Chapter 5 p. 19 says:
“While the PCs are in this area, roll 1d6 every turn. On a roll of 1, there will be a random encounter.”
My understanding is that in the edition this adventure was written, a “turn” corresponds to ten minutes.
Looking at the map, the players will need to traverse about 50 hexes. On page 8 it says it will take the players approximately 3.5 hours to cross each hex.
This means there will be 3.5 * 6 * 50 = 1050 random encounter dice rolls to cross this area. What am I missing?
Thanks for your help!