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*Pathfinder & Starfinder
A solution for multiclass spellcasters? (without PrCs)
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<blockquote data-quote="The Cardinal" data-source="post: 1121560" data-attributes="member: 634"><p>last night I had this idea on how to settle the problems with multiclassing spellcasters - it requires some ultra-simple math, but it may be worth it...</p><p></p><p>Multiclass Spellcasting:</p><p></p><p>To calculate the effective spellcaster level for any given class (i.e. spellslots per day etc.) for a character with more than one spellcasting class do the following:</p><p></p><p>Same type (arcane+arcane, divine+divine): add all spellcasting levels of the same type together, then subtract 3 levels for the first additional class with this type of spellcasting, and 1 for the second – divide that amount by the total number of *all* spellcaster classes and add the result to the spellcaster levels (clr7/dr3/pal2 casts like clr7+(7+3+2-3-1)/3=clr9 and dru3+2=dru5 and pal2+2=4, a clr2/drd4 casts like a clr2+(2+4-3)/2=clr3 and drd4+1=drd5, a wiz5/sorc5 casts like a wiz5+(5+5-3)/2=wiz8 and sorc8)</p><p></p><p>Different type (arcane, divine): (*after* calculating effects for identical spellcasting type) add +1 to arcane spellcaster levels per 3 full levels in divine spellcaster *classes* (not effective caster levels), and vice versa. (so a wiz4/clr3 casts like a wiz5 and a clr4, a sorc9/dru7 casts like a sorc11 and a dru10) </p><p></p><p>mixed examples:</p><p></p><p>Clr4/Wiz5/Sorc7/Drd4 = Wiz (5+(5+7-3)/4)+2= wiz9</p><p> Sorc (7+(5+7-3)/4)+2= sor11</p><p> Clr (4+(4+4-3)/4)+4= clr9</p><p> Drd (4+(4+4-3)/4)+4= drd9</p><p></p><p>Wiz6/Sorc6/Brd5/Clr3 = Wiz (6+(6+6+5-3-1)/4)+1= wiz10</p><p> Sorc (6+(6+6+5-3-1)/4)+1= sor10</p><p> Brd (5+(6+6+5-3-1)/4)+1 = brd9</p><p> Clr 3+5= clr8</p><p></p><p>Sorc14/Wiz3/Clr3 = Wiz (3+(3+14-3)/4)+1= wiz 7</p><p> Sorc (14+(14+3-3)/4)+1= sorc18</p><p> Clr 3+5= clr8</p><p></p><p>Pal5/Clr6/Brd4 = Pal (5+(5+6-3)/3)+1= pal8</p><p> Clr (6+(5+6-3)/3)+1= clr9</p><p> Brd 4+3= brd7 </p><p></p><p></p><p>Comments?</p></blockquote><p></p>
[QUOTE="The Cardinal, post: 1121560, member: 634"] last night I had this idea on how to settle the problems with multiclassing spellcasters - it requires some ultra-simple math, but it may be worth it... Multiclass Spellcasting: To calculate the effective spellcaster level for any given class (i.e. spellslots per day etc.) for a character with more than one spellcasting class do the following: Same type (arcane+arcane, divine+divine): add all spellcasting levels of the same type together, then subtract 3 levels for the first additional class with this type of spellcasting, and 1 for the second – divide that amount by the total number of *all* spellcaster classes and add the result to the spellcaster levels (clr7/dr3/pal2 casts like clr7+(7+3+2-3-1)/3=clr9 and dru3+2=dru5 and pal2+2=4, a clr2/drd4 casts like a clr2+(2+4-3)/2=clr3 and drd4+1=drd5, a wiz5/sorc5 casts like a wiz5+(5+5-3)/2=wiz8 and sorc8) Different type (arcane, divine): (*after* calculating effects for identical spellcasting type) add +1 to arcane spellcaster levels per 3 full levels in divine spellcaster *classes* (not effective caster levels), and vice versa. (so a wiz4/clr3 casts like a wiz5 and a clr4, a sorc9/dru7 casts like a sorc11 and a dru10) mixed examples: Clr4/Wiz5/Sorc7/Drd4 = Wiz (5+(5+7-3)/4)+2= wiz9 Sorc (7+(5+7-3)/4)+2= sor11 Clr (4+(4+4-3)/4)+4= clr9 Drd (4+(4+4-3)/4)+4= drd9 Wiz6/Sorc6/Brd5/Clr3 = Wiz (6+(6+6+5-3-1)/4)+1= wiz10 Sorc (6+(6+6+5-3-1)/4)+1= sor10 Brd (5+(6+6+5-3-1)/4)+1 = brd9 Clr 3+5= clr8 Sorc14/Wiz3/Clr3 = Wiz (3+(3+14-3)/4)+1= wiz 7 Sorc (14+(14+3-3)/4)+1= sorc18 Clr 3+5= clr8 Pal5/Clr6/Brd4 = Pal (5+(5+6-3)/3)+1= pal8 Clr (6+(5+6-3)/3)+1= clr9 Brd 4+3= brd7 Comments? [/QUOTE]
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A solution for multiclass spellcasters? (without PrCs)
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