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<blockquote data-quote="Agback" data-source="post: 2898766" data-attributes="member: 5328"><p>Well, suppose that the foes hit Dextrous monk on A rolls out of 20. If they get a flanking bonus of +1, they will hit on A+1 rolls, which is an increase of 1/A*100%.</p><p></p><p>Exactly the same foes hit Strong Monk on A+1 rolls. With +1 for flanking, they will hit on A+2 rolls out of twenty, which is an increase of 1/(A+1) * 100%.</p><p></p><p>1/A > 1/(A+1).</p><p></p><p>For example, consider a foe that hits Dextrous monk on a roll of 20 only. Given a +1 they will hit twice as oftern, a 100% increase in their damage. The same foehits Strong Monk on a 19, with a +1, on an 18. That's three rolls out of 20 instead of 2, a 50% increase in expected damage.</p><p></p><p></p><p></p><p>They both lose teh fight. Strong Monk does more damage before he drops because he dose 35% more damage per round. 3 * 1.35 = 4.05 > 4.</p><p></p><p></p><p></p><p>I didn't define '20' either. 21 is 21, not a variable.</p><p></p><p>If you nead 20 to hit, you hit on one roll out of 20. If you need nineteen, you hit on two rolls out of twenty, if you need 18, you hit on three rolls out of 20, . . . , if you need a 10, you hit on 11 rolls out of 20, . . . , if you need a 1, you hit on 20 rolls out of twenty. In every case, the number of d20 rolls tht will succeed plus the number you need to roll adds up to 21.</p><p></p><p>The number you need to roll is ac-AB. So where the number of d20 rolls that gives you a success is N, ac-AB+N = 21, therefore N = 21 - ac + AB. Teh probability that you will succeed is N/20 = (21-ac+AB)/20.</p><p></p><p></p><p></p><p>It assumes that they use identical tactics, but not necessarily a static fight. No matter what tactics Dextrous Monk uses, Strong Monk can use the same tactics. He will hit more often, do more damage, put his foes down faster, and suffer fewer counterattacks. A higher proportion of the counterattacks will hit, but Strong monk is still ahead unless the foes have very low AC and very low AB.</p><p></p><p></p><p></p><p>If you want to play an archer, a fighter is a much better choice than a monk.</p><p></p><p></p><p></p><p>Dexrtrous Monk's advantage in tumble checks and reflex saves is 1/A * 100%, where A is his chance of making them. This advantage is only significant where A is small, ie. where the tactic is highly unreliable.</p><p></p><p>Supposing that Dextrous monk has 75% chance to make a tumble check and avoid an AoO, Strong monk has 70%. Strong Monk takes on average 20% more damge from teh occasionally AoO but dishes out 35% more damage on every round in mêlée.</p><p></p><p></p><p></p><p>If you want to play a longbow-using elvish monk you go right ahead. I consider such a build to be a concession that the high-DEX monk is worse in a mêlée than a strong monk, which is the propositionn that you asked me to prove.</p></blockquote><p></p>
[QUOTE="Agback, post: 2898766, member: 5328"] Well, suppose that the foes hit Dextrous monk on A rolls out of 20. If they get a flanking bonus of +1, they will hit on A+1 rolls, which is an increase of 1/A*100%. Exactly the same foes hit Strong Monk on A+1 rolls. With +1 for flanking, they will hit on A+2 rolls out of twenty, which is an increase of 1/(A+1) * 100%. 1/A > 1/(A+1). For example, consider a foe that hits Dextrous monk on a roll of 20 only. Given a +1 they will hit twice as oftern, a 100% increase in their damage. The same foehits Strong Monk on a 19, with a +1, on an 18. That's three rolls out of 20 instead of 2, a 50% increase in expected damage. They both lose teh fight. Strong Monk does more damage before he drops because he dose 35% more damage per round. 3 * 1.35 = 4.05 > 4. I didn't define '20' either. 21 is 21, not a variable. If you nead 20 to hit, you hit on one roll out of 20. If you need nineteen, you hit on two rolls out of twenty, if you need 18, you hit on three rolls out of 20, . . . , if you need a 10, you hit on 11 rolls out of 20, . . . , if you need a 1, you hit on 20 rolls out of twenty. In every case, the number of d20 rolls tht will succeed plus the number you need to roll adds up to 21. The number you need to roll is ac-AB. So where the number of d20 rolls that gives you a success is N, ac-AB+N = 21, therefore N = 21 - ac + AB. Teh probability that you will succeed is N/20 = (21-ac+AB)/20. It assumes that they use identical tactics, but not necessarily a static fight. No matter what tactics Dextrous Monk uses, Strong Monk can use the same tactics. He will hit more often, do more damage, put his foes down faster, and suffer fewer counterattacks. A higher proportion of the counterattacks will hit, but Strong monk is still ahead unless the foes have very low AC and very low AB. If you want to play an archer, a fighter is a much better choice than a monk. Dexrtrous Monk's advantage in tumble checks and reflex saves is 1/A * 100%, where A is his chance of making them. This advantage is only significant where A is small, ie. where the tactic is highly unreliable. Supposing that Dextrous monk has 75% chance to make a tumble check and avoid an AoO, Strong monk has 70%. Strong Monk takes on average 20% more damge from teh occasionally AoO but dishes out 35% more damage on every round in mêlée. If you want to play a longbow-using elvish monk you go right ahead. I consider such a build to be a concession that the high-DEX monk is worse in a mêlée than a strong monk, which is the propositionn that you asked me to prove. [/QUOTE]
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