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<blockquote data-quote="Agemegos" data-source="post: 2902418" data-attributes="member: 18377"><p>Then I miscalculated.</p><p></p><p>Trogs have AB +1. Dextrous Monk has AC 13. Trogs hit on a 12 or better, which is 45%. Trogs do 4.5 hp/hit. 45% of 4.5 is 2.025 hp/trog attack. Trogs have AB +1. Strong Monk has AC 12. Trogs hit on a 11 or better, which is 50%. Trogs do 4.5 hp/hit. 50% of 4.5 is 2.25 hp/trog attack. In avoiding damage, the advantage is to Dextrous Monk by 0.225/2.25 = 10%. This is independent of the number of trogs.</p><p></p><p>Trogs have AC 14. Strong Monk has AB +5 (with kama). Strong Monk hits on a 9 or better, which is 60% of the time. Strong Monk does d6+3, which averages 6.5. 60% times 6.5 is 3.9 hp/turn. Trogs have AC 14. Dextrous Monk has AB +4 (with kama). Dextrous Monk hits on a 10 or better, which is 55% of the time. Dextrous Monk does d6+2, which averages 5.5. 55% times 5.5 is 3.025 hp/turn. In dishing out damage, the advantage is to Strong Monk by 0.875/3.9 =23.4%, regardless of the number of trogs.</p><p></p><p>So regardless of the number of trogs, Strong Monk has a greater advantage. The ratio of damage suffered to damage done is what counts, and Strong Monk's ratio is better than Dextrous Monk's ratio by 20.4%. If there are enough trogs to beat either monk, Strong Monk does 20% more damage than Dextrous Monk. If there are few enough trogs that the monk wins, Strong Monk takes 17% less damage than Dextrous Monk. Somewhere in the middle, there is a fight that Strong Monk wins but that Dextrous Monk loses.</p><p></p><p></p><p></p><p>You can if you like, but there is no point. I have done the algebra, I know how the numbers will turn out. The number of opponents doesn't matter. Strong Monk's advantage to hit gets bigger as the targets get harder to hit. Dextrous Monk's advantage to avoid damage gets smaller as the <em>monks</em> get harder to hit. And the opponents have to be feeble indeed before Dextrous Monk's advantage in avoiding damage overcomes both Strong Monk's advantage in hitting and his advantage in damage per hit.</p></blockquote><p></p>
[QUOTE="Agemegos, post: 2902418, member: 18377"] Then I miscalculated. Trogs have AB +1. Dextrous Monk has AC 13. Trogs hit on a 12 or better, which is 45%. Trogs do 4.5 hp/hit. 45% of 4.5 is 2.025 hp/trog attack. Trogs have AB +1. Strong Monk has AC 12. Trogs hit on a 11 or better, which is 50%. Trogs do 4.5 hp/hit. 50% of 4.5 is 2.25 hp/trog attack. In avoiding damage, the advantage is to Dextrous Monk by 0.225/2.25 = 10%. This is independent of the number of trogs. Trogs have AC 14. Strong Monk has AB +5 (with kama). Strong Monk hits on a 9 or better, which is 60% of the time. Strong Monk does d6+3, which averages 6.5. 60% times 6.5 is 3.9 hp/turn. Trogs have AC 14. Dextrous Monk has AB +4 (with kama). Dextrous Monk hits on a 10 or better, which is 55% of the time. Dextrous Monk does d6+2, which averages 5.5. 55% times 5.5 is 3.025 hp/turn. In dishing out damage, the advantage is to Strong Monk by 0.875/3.9 =23.4%, regardless of the number of trogs. So regardless of the number of trogs, Strong Monk has a greater advantage. The ratio of damage suffered to damage done is what counts, and Strong Monk's ratio is better than Dextrous Monk's ratio by 20.4%. If there are enough trogs to beat either monk, Strong Monk does 20% more damage than Dextrous Monk. If there are few enough trogs that the monk wins, Strong Monk takes 17% less damage than Dextrous Monk. Somewhere in the middle, there is a fight that Strong Monk wins but that Dextrous Monk loses. You can if you like, but there is no point. I have done the algebra, I know how the numbers will turn out. The number of opponents doesn't matter. Strong Monk's advantage to hit gets bigger as the targets get harder to hit. Dextrous Monk's advantage to avoid damage gets smaller as the [i]monks[/i] get harder to hit. And the opponents have to be feeble indeed before Dextrous Monk's advantage in avoiding damage overcomes both Strong Monk's advantage in hitting and his advantage in damage per hit. [/QUOTE]
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