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General Tabletop Discussion
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Anyone figured out math to remove extra attacks?
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<blockquote data-quote="Madeiner" data-source="post: 6621698" data-attributes="member: 61624"><p>I worked some more math and finally found the formula that would allow me to do this.</p><p>In doing that, i realized it's probably just as fast as having multiple attack, especially when i have to adjudicate all those things.</p><p>(Sneak attack came to mind, where the rogue is more interested in having at least one attack hit, then in anything else)</p><p></p><p><strong>The formula, for whoever is interested from a purely academic standpoint, is easy:</strong></p><p></p><p><strong>Add N to an attack roll</strong>. For example, 5. </p><p>Note 2 different ACs for monster; The normal AC, and its AC + N (AC + 10 is easy to remember, if you use N=5)</p><p></p><p><strong>Rewrite attacks on the sheet</strong> so that based on the amount of attacks you do with a single action, you deal different damage.</p><p>If you have two attacks, you do 1x damage on AC hit, and x2 amount on AC+10 hit.</p><p>If you have three attacks, you do 1.5x damage on AC hit, and x3 damage on AC+10 hit.</p><p>Etcetera.</p><p></p><p><strong>However, all things considered</strong> (having reaction use different damage or modifier than an attack action, for example, monk styles, sneak attacks),<strong> i will stick with the normal system.</strong></p><p>Still it was fun to try and calculate it <img src="https://cdn.jsdelivr.net/joypixels/assets/8.0/png/unicode/64/1f600.png" class="smilie smilie--emoji" loading="lazy" width="64" height="64" alt=":D" title="Big grin :D" data-smilie="8"data-shortname=":D" /></p></blockquote><p></p>
[QUOTE="Madeiner, post: 6621698, member: 61624"] I worked some more math and finally found the formula that would allow me to do this. In doing that, i realized it's probably just as fast as having multiple attack, especially when i have to adjudicate all those things. (Sneak attack came to mind, where the rogue is more interested in having at least one attack hit, then in anything else) [B]The formula, for whoever is interested from a purely academic standpoint, is easy:[/B] [B]Add N to an attack roll[/B]. For example, 5. Note 2 different ACs for monster; The normal AC, and its AC + N (AC + 10 is easy to remember, if you use N=5) [B]Rewrite attacks on the sheet[/B] so that based on the amount of attacks you do with a single action, you deal different damage. If you have two attacks, you do 1x damage on AC hit, and x2 amount on AC+10 hit. If you have three attacks, you do 1.5x damage on AC hit, and x3 damage on AC+10 hit. Etcetera. [B]However, all things considered[/B] (having reaction use different damage or modifier than an attack action, for example, monk styles, sneak attacks),[B] i will stick with the normal system.[/B] Still it was fun to try and calculate it :D [/QUOTE]
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Anyone figured out math to remove extra attacks?
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