Reply to thread

Message

<blockquote data-quote="GMMichael" data-source="post: 7646206" data-attributes="member: 6685730">Since this is similar to exploding dice, and this necro-thread has yet to meet a cleric, here's another one for you probability pros:What is the average result, based on the number you must exceed (target number), of a d20 that you get to re-roll as long as your first roll was higher than the target, and your following roll is higher than your previous roll?The process goes like this:Target number is 10.&nbsp; So if you roll a 10 or lower, that's your result.Roll a 15, and you get to roll again, because you beat the target number.Roll 8 after that, and your 15 stands.&nbsp; Roll 19, and you get to roll again.Roll 20 and...just kidding.&nbsp; You're not going to roll a 20 after a 19.So the result of that process was 19, based on a target number of 10.&nbsp; Which means my question is horribly bad, and should be more like:What are the odds of getting a 20 result, based on the target number, using the above process?orWhat is the average number of re-rolls allowed, based on the target number, using the above process?The idea is that if you beat your own result, you get a better outcome (critical).&nbsp; Obviously, &quot;beat yourself&quot; was not a viable name.&nbsp; So I've been calling it a &quot;quality contest,&quot; which lacks the zing of &quot;exploding dice.&quot;&nbsp; Name suggestions are welcome, too.</blockquote>

[QUOTE="GMMichael, post: 7646206, member: 6685730"] Since this is similar to exploding dice, and this necro-thread has yet to meet a cleric, here's another one for you probability pros: What is the average result, based on the number you must exceed (target number), of a d20 that you get to re-roll as long as your first roll was higher than the target, and your following roll is higher than your previous roll? The process goes like this: Target number is 10. So if you roll a 10 or lower, that's your result. Roll a 15, and you get to roll again, because you beat the target number. Roll 8 after that, and your 15 stands. Roll 19, and you get to roll again. Roll 20 and...just kidding. You're not going to roll a 20 after a 19. So the result of that process was 19, based on a target number of 10. Which means my question is horribly bad, and should be more like: [B]What are the odds of getting a 20 result, based on the target number, using the above process? or What is the average number of re-rolls allowed, based on the target number, using the above process? [/B] The idea is that if you beat your own result, you get a better outcome (critical). Obviously, "beat yourself" was not a viable name. So I've been calling it a "quality contest," which lacks the zing of "exploding dice." Name suggestions are welcome, too. [/QUOTE]

Verification