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Message: <blockquote data-quote="Drawmack" data-source="post: 399741" data-attributes="member: 4981">I am planning on doing up an adventure that takes place at a carnival. There will be bets taken on a number of the contests and in order to calculate the odds of winning accuratly I need to calculate the odds of the die rolls. So this thread is for discussion on this topic. The odds of a calculating a single roll in D&D are a matter of simple algebra. Here are some examples.1) Hitting: (20 + Attack Bonus - AC) * 52) Completing a task: (20 + Modifiers - DC) * 53) Opposed Rolls: ((X*X)/2) * (100/(S*S)) (underdog winning)X = 20 - (Higher Bonus - Smaller Bonus)S = # sides on the die.For example:A 1st level fighter str 12 rolls a d20+2 against an ORC (AC 14). The odds that this is going to hit is (20 + 2 - 14) * 5 = 8 * 40 = 40% chance to hit the orc.A 1st level rogue with wis 12 and four ranks in disable device attempts to disarm a trap with a DC 15. The of this working are (20 + 5 - 15) * 5 = 10 * 5 = 50% chance of disarming the trap.A commoner with str 18 (+4) arm wrestles a commoner str 3 (-4). The odds of this working are (((20 - (4 - -4)) *(20 - (4 - -4)))/2 * (100/(20*20) = ((12 * 12)/2) * (100/400) = (144/2) * .25 = 72 * .25 = 18%. There is an 18% chance that the underdog will win and a 72% chance that the favorite will win.Now we reach the point where my mathematical skills begin to break down. I have two types of odds left to calculate and I don't know how to do it. The two types that I wish to calculate yet are. More then two characters doing a single opposed die roll and two characters doing multiple opposed die rolls.</blockquote>

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