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Can you CHOOSE to turn your spell into a full-round action?
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<blockquote data-quote="The Sigil" data-source="post: 148590" data-attributes="member: 2013"><p><strong>Circular logic...</strong></p><p></p><p></p><p>Except you have not invoked Identity. You have fallen into logical fallacy in attemptin to translate words into mathematical symbols. Let me re-state your premises, adding the one critical word you have missed...</p><p></p><p>1.) All Standard Actions are PA + MEA (definition)</p><p></p><p>2.) All Double Moves are SOME standard actions (by definition; note your critical ommission of the word SOME)</p><p></p><p>In other words, you have</p><p>A (All Standard Actions)</p><p>B (PA + MEA)</p><p>C (All Double Moves)</p><p>D (SOME Standard Actions)</p><p></p><p>It should be clear that what you have here A = B and C = D, not</p><p>A = B and C = A (as you claim). Therefore there is no identity to invoke.</p><p></p><p>This is why I have said that in order to invoke identity on your argument you must have the phrase "All Double Moves are All Standard Actions" because it is only in that phrase that you will find the A = B and A = C pair you so desperately need.</p><p></p><p></p><p></p><p>I have *never* granted you that you have this equivalency with respect to time (i.e., that PAs and MEAs take the same amount of time to perform. This assertion comes from circular reasoning... you assert that...</p><p></p><p>MEA = PA</p><p>therefore MEA = 3 sec and PA = 3 sec</p><p>therefore, since both are 3 sec, </p><p>MEA = PA.</p><p></p><p>Or did your professors not catch that one? <img src="https://cdn.jsdelivr.net/joypixels/assets/8.0/png/unicode/64/1f642.png" class="smilie smilie--emoji" loading="lazy" width="64" height="64" alt=":)" title="Smile :)" data-smilie="1"data-shortname=":)" /> </p><p></p><p>I do not grant you that an MEA = PA because you *have not proved* it. </p><p></p><p>I will stand with my original statement that if you must drag time into it, a PA is 3.5 sec and an MEA is 2.5 sec... and you cannot use temporal arguments to prove to the contrary... you can merely say, "well, since I say MEA = PA (which as I have demonstrated repeatedly is a logically flawed conclusion), you're wrong." Sorry, I will not accept "you are wrong by my fiat" argument.</p><p></p><p>--The Sigil</p></blockquote><p></p>
[QUOTE="The Sigil, post: 148590, member: 2013"] [b]Circular logic...[/b] Except you have not invoked Identity. You have fallen into logical fallacy in attemptin to translate words into mathematical symbols. Let me re-state your premises, adding the one critical word you have missed... 1.) All Standard Actions are PA + MEA (definition) 2.) All Double Moves are SOME standard actions (by definition; note your critical ommission of the word SOME) In other words, you have A (All Standard Actions) B (PA + MEA) C (All Double Moves) D (SOME Standard Actions) It should be clear that what you have here A = B and C = D, not A = B and C = A (as you claim). Therefore there is no identity to invoke. This is why I have said that in order to invoke identity on your argument you must have the phrase "All Double Moves are All Standard Actions" because it is only in that phrase that you will find the A = B and A = C pair you so desperately need. I have *never* granted you that you have this equivalency with respect to time (i.e., that PAs and MEAs take the same amount of time to perform. This assertion comes from circular reasoning... you assert that... MEA = PA therefore MEA = 3 sec and PA = 3 sec therefore, since both are 3 sec, MEA = PA. Or did your professors not catch that one? :) I do not grant you that an MEA = PA because you *have not proved* it. I will stand with my original statement that if you must drag time into it, a PA is 3.5 sec and an MEA is 2.5 sec... and you cannot use temporal arguments to prove to the contrary... you can merely say, "well, since I say MEA = PA (which as I have demonstrated repeatedly is a logically flawed conclusion), you're wrong." Sorry, I will not accept "you are wrong by my fiat" argument. --The Sigil [/QUOTE]
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Can you CHOOSE to turn your spell into a full-round action?
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