Reply to thread

Message

<blockquote data-quote="Hypersmurf" data-source="post: 3327217" data-attributes="member: 1656">No, the premise of taking 20 is that you stop once you've taken twenty times as long, with a result calculated as though you had rolled a 20.Let's use Open Lock again as an example - normally a full round action.If there is a lock with a DC of 30, and your Open Lock modifier is +5, then &quot;you stop once you finally succeed&quot; would mean you would keep attempting to open the lock forever, because you will never succeed.Rather, you stop after 20 rounds have passed (having failed repeatedly along the way), and compare your result (20 + 5 = 25) with the DC.It's possible to Take 20 and fail; but you know that the failure was with your maximum result.&nbsp; It's also possible to Take 20 and succeed; and again, you know that the success was with your maximum result.If I have an unknown lock, I don't know whether Take 20 will result in success or failure, but I know that either way, it will result in a 25.-Hyp.</blockquote>

[QUOTE="Hypersmurf, post: 3327217, member: 1656"] No, the premise of taking 20 is that you stop once you've taken twenty times as long, with a result calculated as though you had rolled a 20. Let's use Open Lock again as an example - normally a full round action. If there is a lock with a DC of 30, and your Open Lock modifier is +5, then "you stop once you finally succeed" would mean you would keep attempting to open the lock forever, because you will never succeed. Rather, you stop after 20 rounds have passed (having failed repeatedly along the way), and compare your result (20 + 5 = 25) with the DC. It's possible to Take 20 and fail; but you know that the failure was with your maximum result. It's also possible to Take 20 and succeed; and again, you know that the success was with your maximum result. If I have an unknown lock, I don't know whether Take 20 will result in success or failure, but I know that either way, it will result in a 25. -Hyp. [/QUOTE]

Verification