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<blockquote data-quote="NotAYakk" data-source="post: 8364861" data-attributes="member: 72555"><p>"Sink"? Sink where? You mean, the water will pull you inside itself when you are at the edge of it?</p><p></p><p>Even then -- <a href="https://pubs.acs.org/doi/abs/10.1021/cen-v045n018.p024" target="_blank">https://pubs.acs.org/doi/abs/10.1021/cen-v045n018.p024</a> -- our skin is highly hydrophobic. Unless you are caked in dirt, the clean surface area is going to win. So surface tension will make it want to wrap around us (minimal surface area), it won't be hard to shake loose.</p><p></p><p>If there is enough water to swim in, I'd expect that the hydrophillic/phobic and surface tension effects aren't going to be large compared to the thrust of a swimmer. </p><p></p><p>I did make a surface tension error. It is actually in force/distance, as the output is energy when multiplied by the increase in surface area.</p><p></p><p>So, suppose you try to breach a water membrane. You want to make a tube 0.5 m diameter that is about 2 m long, representing the water you drag along with you as you break free. Then you want to snip it off. Assuming the source water is large, the new surface area is then 2 pi * (0.5m)^2 for the "caps" and pi * 2m^2 for the "long part", or 8 m^2. (The goal is order of magnitude).</p><p></p><p>Water is 72 mN/m. So this is all of 0.576 Joules. That isn't all that much.</p><p></p><p>I suspect the fact that swimming will make the water start to mix with the air (internal currents overwealm surface tension) making it hard to swim before that becomes a problem. But I could be wrong.</p></blockquote><p></p>
[QUOTE="NotAYakk, post: 8364861, member: 72555"] "Sink"? Sink where? You mean, the water will pull you inside itself when you are at the edge of it? Even then -- [URL]https://pubs.acs.org/doi/abs/10.1021/cen-v045n018.p024[/URL] -- our skin is highly hydrophobic. Unless you are caked in dirt, the clean surface area is going to win. So surface tension will make it want to wrap around us (minimal surface area), it won't be hard to shake loose. If there is enough water to swim in, I'd expect that the hydrophillic/phobic and surface tension effects aren't going to be large compared to the thrust of a swimmer. I did make a surface tension error. It is actually in force/distance, as the output is energy when multiplied by the increase in surface area. So, suppose you try to breach a water membrane. You want to make a tube 0.5 m diameter that is about 2 m long, representing the water you drag along with you as you break free. Then you want to snip it off. Assuming the source water is large, the new surface area is then 2 pi * (0.5m)^2 for the "caps" and pi * 2m^2 for the "long part", or 8 m^2. (The goal is order of magnitude). Water is 72 mN/m. So this is all of 0.576 Joules. That isn't all that much. I suspect the fact that swimming will make the water start to mix with the air (internal currents overwealm surface tension) making it hard to swim before that becomes a problem. But I could be wrong. [/QUOTE]
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