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Message: <blockquote data-quote="Asmor" data-source="post: 3814882" data-attributes="member: 1154">[sblock=nm, error]Note: C(n, k) means choose Y elements from X possible elements. Below, the elements are dice, and we're choosing which dice are rolling 6s.C(n, k)=n!/(k!(n-k)!)Rolling 3 dice:Choose three dice to roll six: C(3, 3): 1Total ways to roll 18: 1Total possible rolls: 6^3=216Possibility of 18: 1/216=0.46%Rolling 4 dice:Choose three dice to roll six: C(4, 3): 4Possible combinations of remaining die: 6Total ways to roll 18: 4*6=24Total possible rolls: 6^4=1296Possibility of 18: 24/1296=1.85%Rolling 5 dice:Choose three dice to roll six: C(5, 3): 10Possible combinations of remaining 2 dice: 6^2=36Total ways to roll 18: 10*36=360Total possible rolls: 6^5=7776Possibility of 18: 360/7776=4.63%Hopefully you can extrapolate this to whatever amount of dice you might want to roll. Note that this is the possibility of rolling 18 on one roll... If you're looking for the possibility by character, just multiply the percentages by 6 (for 6 scores)[/sblock]Hmm, I screwed up somewhere... Just remembered that there's 21 possible ways to roll an 18 on 4d6, and my reasoning above leads to 24. Anyone with a background in statistics see what I did wrong?</blockquote>