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Message: <blockquote data-quote="dave2008" data-source="post: 7832004" data-attributes="member: 83242">I'm not sure what you are getting at, but Legendary actions do not change a monster's CR.  They simple make it more dynamic and allows it to get an action (or two or three) off turn.However, bounded accuracy doesn't prevent higher CR monsters from anything.  5e is balanced around HP not AC.  The monster may be able to be hit easier (WotC seems to think that is more fun than missing), but the monster should have higher HP to compensate.   Higher CR monsters are more difficult to take down and hit harder in 5e.  The accuracy of those attacks just don't scale as much.  The big difference with PF2e is that it happens about 2x as quickly vs 5e (which I personally don't like, but whatever).  Higher level monsters are harder to hit, have more HP, hit harder, and do more damage in PF2e, while the advancement on 5e is primarily through HP and DPR (though I think they went low on the DPR scale).  So if a solo is 2-4 levels higher in PF2e it is about 4-8 (personally I use 5-10) CR higher than party level on 5e.  However, they achieve very similar results.This holds true whether or not a monster is a "solo" which isn't a term in 5e anyway.  If you take a balor against a lvl 10 party in 5e I can  assure it feels like a boss fight without legendary actions (I know as it was the boss fight for when my group of  6PCS were 10th level).  But it would be even better if it had legendary actions.White room example of 4 10th level PCs vs balor (CR 19)[spoiler]Very basic and rudimentary look at this type of boss battle just to show how close numerically the battle can be.  FYI, I left out damage resistance in this which would obviously skew the result widely in the balor's favor.10th lvl fighter (4)HP 90AC 20Attack bonus +9DPR 6.5+5=11.5 x 2 = 23 (46 w/ action surge)Balor:HP 262AC 19Attack bonus +14DPR: 35 +10 + 28 = 73 DPRRD 1Fighter x4 = 46x4 = 184*.5 = 92 damage (balor at 204)Balor = 73 *.7 = 51 damage (fighter 1 at 39 HP)RD 2Fighter x4 = 23x4 = 92*.5 = 46 damage (balor at 158)Balor = 73 *.7 = 51 damage (fighter 1 dead)RD 3Fighter x3 = 23x3 = 69*.5 = 34 damage (balor at 124)Balor = 73 *.7 = 51 damage (fighter 2 at 39 HP)RD 4Fighter x3 = 23x4 = 69*.5 = 34 damage (balor at 90)Balor = 73 *.7 = 51 damage (fighter 2 dead)RD 5Fighter x2 = 23x2 = 46*.5 = 23 damage (balor at 67)Balor = 73 *.7 = 51 damage (fighter 3 at 39 HP)RD 6Fighter x2 = 23x2 = 46*.5 = 23 damage (balor at 44)Balor = 73 *.7 = 51 damage (fighter 3 dead)RD 7Fighter = 23 = 23*.5 = 11 damage (balor at 33)Balor = 73 *.7 = 51 damage (fighter 4 at 39)RD 8Fighter = 23 = 23*.5 = 11 damage (balor at 22)Balor = 73 *.7 = 51 damage (fighter 4 dead)[/spoiler]</blockquote>

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