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<blockquote data-quote="Splart" data-source="post: 4409236" data-attributes="member: 12316">Huh.&nbsp; I'm impressed with your deep knowledge of the books.&nbsp; So, this would apply even if the ranger used an action point to get 4 attacks in a round.&nbsp; Funky.&nbsp; So, is that a feature of the ranger only, or is that a feature of all &quot;quarry-like&quot; attacks?&nbsp; I.e. does the rogue/ranger get the same benefit from this, or does he have to name which dice is the &quot;first&quot; sneak attack, and only gets crit damage if rolled on that one?According to RAW, I would say no, so the quarry probability formulas have to be made separate for the ranger versus the rogue/ranger.In any case, for the ranger at least, the formula then becomes:(1-(1-PCrit)^PCattacks)*crit quarry dmg + (1-(1-PHit)^PCattacks - 2 * PCrit * PHit) * average quarry dmg The problem with your reasoning is that the chance not getting a crit attack includes the chance of missing totally, which is not accurate when the rest of the calculation assumes at least one hit.&nbsp; It's like the old math problem -- I have two children and at least one boy:&nbsp; what is the chance I have two boys?&nbsp; According to the reasoning you used, the answer is 50% * 50% = 25%, but the correct answer is 33%, because there are three equal probability combinations that meet the 1 boy condition, boy-boy, boy-girl, and girl-boy.&nbsp; In this calculation, when you have already included the condition that one attack hits (1-(1-PHit)^PCAttacks), multiplying this by the chance that no crits hit (1-(1-PCrit)^PCAttacks) doesn't work because the no crit chance includes the chance that both attacks miss.--Splart</blockquote>

[QUOTE="Splart, post: 4409236, member: 12316"] Huh. I'm impressed with your deep knowledge of the books. So, this would apply even if the ranger used an action point to get 4 attacks in a round. Funky. So, is that a feature of the ranger only, or is that a feature of all "quarry-like" attacks? I.e. does the rogue/ranger get the same benefit from this, or does he have to name which dice is the "first" sneak attack, and only gets crit damage if rolled on that one? According to RAW, I would say no, so the quarry probability formulas have to be made separate for the ranger versus the rogue/ranger. In any case, for the ranger at least, the formula then becomes: (1-(1-PCrit)^PCattacks)*crit quarry dmg + (1-(1-PHit)^PCattacks - 2 * PCrit * PHit) * average quarry dmg The problem with your reasoning is that the chance not getting a crit attack includes the chance of missing totally, which is not accurate when the rest of the calculation assumes at least one hit. It's like the old math problem -- I have two children and at least one boy: what is the chance I have two boys? According to the reasoning you used, the answer is 50% * 50% = 25%, but the correct answer is 33%, because there are three equal probability combinations that meet the 1 boy condition, boy-boy, boy-girl, and girl-boy. In this calculation, when you have already included the condition that one attack hits (1-(1-PHit)^PCAttacks), multiplying this by the chance that no crits hit (1-(1-PCrit)^PCAttacks) doesn't work because the no crit chance includes the chance that both attacks miss. --Splart [/QUOTE]

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