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(Discussion) Character Points Change Issue
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<blockquote data-quote="Creamsteak" data-source="post: 1597361" data-attributes="member: 552"><p>No, your missing the elegance of a simpler program design. You don't need to run 6^24 binary comparisons to check each total, you need to run 15^6 by simplifying the algorithm. And you only need a few kilobytes of memory to run it as well. Look at the equation from the end result (6 different sets with 3 to 18 listed) and you can simplify it based on that. That's what I've done, but a more precise language can do the same thing only vastly more precise. If I took something to the second double precision instead of the first, I could technically calculate it with less than a billionth of error.</p><p></p><p>And taking just 1 ability scores average points value for all results will not yield you the results for two reasons. 1) You can't take criteria like "one ability must be greater than 13" into consideration, and 2) Since point buy is non-differential, you can't break it down into a linear equation that breaks up evenly, so since 18s and 17s are worth more than 14s and 9s, you get a total which is related to the most common values 12-14 that will dominate the single instance, but not all instances that exist for 6 arrays.</p><p></p><p>Now, the only speculation left is what to do with abilities less than 8? Do you factor them in as 0s or as negative scores?</p></blockquote><p></p>
[QUOTE="Creamsteak, post: 1597361, member: 552"] No, your missing the elegance of a simpler program design. You don't need to run 6^24 binary comparisons to check each total, you need to run 15^6 by simplifying the algorithm. And you only need a few kilobytes of memory to run it as well. Look at the equation from the end result (6 different sets with 3 to 18 listed) and you can simplify it based on that. That's what I've done, but a more precise language can do the same thing only vastly more precise. If I took something to the second double precision instead of the first, I could technically calculate it with less than a billionth of error. And taking just 1 ability scores average points value for all results will not yield you the results for two reasons. 1) You can't take criteria like "one ability must be greater than 13" into consideration, and 2) Since point buy is non-differential, you can't break it down into a linear equation that breaks up evenly, so since 18s and 17s are worth more than 14s and 9s, you get a total which is related to the most common values 12-14 that will dominate the single instance, but not all instances that exist for 6 arrays. Now, the only speculation left is what to do with abilities less than 8? Do you factor them in as 0s or as negative scores? [/QUOTE]
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