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<blockquote data-quote="Maxperson" data-source="post: 7363756" data-attributes="member: 23751">The slug gets a save.It's not 100% that you will encounter disintegrate.&nbsp; Maybe it is in your games, but it's not a guarantee for other people's campaigns.&nbsp; It's not 100% that the druid will be wildshaped.&nbsp; It's not 100% that the druid will be targeted.&nbsp; And it's very likely that at that level, the druid will make his save.That doesn't say what you think it says.&nbsp; You are ignoring context, which is fail.&nbsp; You're basically give me fake news.&nbsp; The sentence immediately prior is a part of what line 15 means.&nbsp; Here are both sentences.&quot;However, if you revert as a result of dropping to 0 hit points, any excess damage carries over to your normal form. For example, if you take 10 damage in animal form and have only 1 hit point left, you revert and take 9 damage.&quot;The bolded portion cannot be ignored.&nbsp; It explicitly says that you revert as a result of dropping to 0.&nbsp; Line 15 is also about dropping to 0, because the context of the entire paragraph requires it to be so.&nbsp; Heck, even in isolation it's about dropping to 0.&nbsp; If you are at 1 and take 10 damage, and you revert at 1hp, you cannot then take 9.&nbsp; Since you reverted at 1, no damage from the 10 has yet been applied, so by your explanation, it would require 10 hit points to be removed from the reverted druid.&nbsp; That 1 point didn't just vanish.&nbsp; No, line 15 requires that 1 hit point to go to 0, then revert and finish the final 9 hit points.&nbsp; That's quite literally the only way 10 damage can be applied and result in 9 damage to the druid's normal form.</blockquote>

[QUOTE="Maxperson, post: 7363756, member: 23751"] The slug gets a save. It's not 100% that you will encounter disintegrate. Maybe it is in your games, but it's not a guarantee for other people's campaigns. It's not 100% that the druid will be wildshaped. It's not 100% that the druid will be targeted. And it's very likely that at that level, the druid will make his save. That doesn't say what you think it says. You are ignoring context, which is fail. You're basically give me fake news. The sentence immediately prior is a part of what line 15 means. Here are both sentences. "However, [B]if you revert as a result of dropping to 0 hit points[/B], any excess damage carries over to your normal form. For example, if you take 10 damage in animal form and have only 1 hit point left, you revert and take 9 damage." The bolded portion cannot be ignored. It explicitly says that you revert as a result of dropping to 0. Line 15 is also about dropping to 0, because the context of the entire paragraph requires it to be so. Heck, even in isolation it's about dropping to 0. If you are at 1 and take 10 damage, and you revert at 1hp, you cannot then take 9. Since you reverted at 1, no damage from the 10 has yet been applied, so by your explanation, it would require 10 hit points to be removed from the reverted druid. That 1 point didn't just vanish. No, line 15 requires that 1 hit point to go to 0, then revert and finish the final 9 hit points. That's quite literally the only way 10 damage can be applied and result in 9 damage to the druid's normal form. [/QUOTE]

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