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Effects and conditions stack
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<blockquote data-quote="CapnZapp" data-source="post: 5001908" data-attributes="member: 12731"><p>For the record, this isn't what I was saying.</p><p></p><p>My houserule means: If you are already dazed, being dazed again probably results in you being dazed <em>longer</em>.</p><p></p><p>That is, getting rid of a condition is harder when you need to save twice.</p><p></p><p>There is no notion of being "more dazed" involved.</p><p></p><p></p><p>Wow. You can really save yourself a few brainwaves by off-loading this duty onto your players, did you know that?</p><p> </p><p></p><p></p><p>Well, that's not exactly my point. </p><p></p><p>My point is that the game (through this rule) makes an encounter with AAAAA easier than an encounter with ABCDE, purely because chances are that if you suffer from ability A you can still be hit with ability B.</p><p></p><p>This I call a "nerf" against encounters with several identical monsters.</p><p></p><p>Of course, some might think it is actually a good idea, because it offers a reason for monsters to diversify. </p><p></p><p>As for myself, I see no inherent reason why the AAAAA encounter should be significantly easier than other encounters, just because the A condition doesn't stack with itself.</p><p> </p><p></p><p>No, it <em>can't</em> be overpowered. The DMG guidelines never assigns penalty XP to encounters with several different monsters all capable of throwing out a variation of a condition like Dazed.</p><p></p><p>If monsters A, B, C, D and E are all worth 1,000 XP; then both encounters AAAAA and ABCDE are worth 5,000 XP.</p><p></p><p>I see no general design tendency that identical monsters would make a condition overpowered - as far as I can see, such an encounter would be functionally identical to another encounter where all monsters just happen to be able to throw out a variation of one and the same condition.</p><p></p><p>In other words, just like you might want to keep an eye out for ABCDE encounters where all monsters can stun you, now you also keep an eye out for AAAAA encounters (or DDDDD encounters) because all monsters can still stun you.</p><p></p><p>In summary, I think this rule is there for simplicity only. Only that for me, it actually feels more like a mess than a solution.</p><p></p><p>Hence my houserule! <img src="https://cdn.jsdelivr.net/joypixels/assets/8.0/png/unicode/64/1f642.png" class="smilie smilie--emoji" loading="lazy" width="64" height="64" alt=":)" title="Smile :)" data-smilie="1"data-shortname=":)" /></p></blockquote><p></p>
[QUOTE="CapnZapp, post: 5001908, member: 12731"] For the record, this isn't what I was saying. My houserule means: If you are already dazed, being dazed again probably results in you being dazed [I]longer[/I]. That is, getting rid of a condition is harder when you need to save twice. There is no notion of being "more dazed" involved. Wow. You can really save yourself a few brainwaves by off-loading this duty onto your players, did you know that? Well, that's not exactly my point. My point is that the game (through this rule) makes an encounter with AAAAA easier than an encounter with ABCDE, purely because chances are that if you suffer from ability A you can still be hit with ability B. This I call a "nerf" against encounters with several identical monsters. Of course, some might think it is actually a good idea, because it offers a reason for monsters to diversify. As for myself, I see no inherent reason why the AAAAA encounter should be significantly easier than other encounters, just because the A condition doesn't stack with itself. No, it [I]can't[/I] be overpowered. The DMG guidelines never assigns penalty XP to encounters with several different monsters all capable of throwing out a variation of a condition like Dazed. If monsters A, B, C, D and E are all worth 1,000 XP; then both encounters AAAAA and ABCDE are worth 5,000 XP. I see no general design tendency that identical monsters would make a condition overpowered - as far as I can see, such an encounter would be functionally identical to another encounter where all monsters just happen to be able to throw out a variation of one and the same condition. In other words, just like you might want to keep an eye out for ABCDE encounters where all monsters can stun you, now you also keep an eye out for AAAAA encounters (or DDDDD encounters) because all monsters can still stun you. In summary, I think this rule is there for simplicity only. Only that for me, it actually feels more like a mess than a solution. Hence my houserule! :) [/QUOTE]
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