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<blockquote data-quote="hirumachico" data-source="post: 7624222" data-attributes="member: 6989365">Reading this again as I prepare for running my first ever WOIN game tomorrow.&nbsp; I now see something I missed before:&nbsp; &quot;Equal total MDP on each side makes for a medium encounter.&quot;&nbsp; My emphasis added, I missed that I should be adding all of the total MDPs together.&nbsp; Therefore a boss villain at 8d6 and his 4 henchmen at 5d6 that equals 28d6 vs. my PC team of 4 x Grade 10's (7d6 each) equals 28d6 is the evenly matched scenario, which means a medium encounter.&nbsp; And as long as the totals of MDPs are closely matched this is a medium encounter.&nbsp; But if I were to modify my prior example by adding one additional 5d6 MDP henchman or just making the boss villain an 11d6 instead of an 8d6, the PCs are facing a deadly encounter.&nbsp; Just want to be sure I've got the concept right.&nbsp; Thanks for reading (and hopefully setting me straight).</blockquote>

[QUOTE="hirumachico, post: 7624222, member: 6989365"] Reading this again as I prepare for running my first ever WOIN game tomorrow. I now see something I missed before: "Equal [B][U]total MDP on each side[/U][/B] makes for a medium encounter." My emphasis added, I missed that I should be adding all of the total MDPs together. Therefore a boss villain at 8d6 and his 4 henchmen at 5d6 that equals 28d6 vs. my PC team of 4 x Grade 10's (7d6 each) equals 28d6 is the evenly matched scenario, which means a medium encounter. And as long as the totals of MDPs are closely matched this is a medium encounter. But if I were to modify my prior example by adding one additional 5d6 MDP henchman or just making the boss villain an 11d6 instead of an 8d6, the PCs are facing a deadly encounter. Just want to be sure I've got the concept right. Thanks for reading (and hopefully setting me straight). [/QUOTE]

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