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<blockquote data-quote="merwins" data-source="post: 7105219" data-attributes="member: 6829883"><p>Just as a thought experiment. </p><p></p><p>I'm trying to determine how many hangers-on a character could have in 5E. </p><p></p><p>Obviously, this would require multi-classing. I have listed the minimum character level to the left of each line. </p><p></p><p>(Level 1) Many spellcasting classes have Find Familiar. Find Familiar doesn't stack. You get one, no matter how many classes offer the spell. </p><p></p><p>(Level 5) Paladin gets Find Steed. </p><p></p><p>(Level 3) Ranger gets a beast companion. </p><p></p><p>(Level 3) Both Bard and Druid have access to the 1st level Animal Friendship (don't hurt me) and the 2nd level Animal Messenger (deliver this) fixed function companion spells. </p><p></p><p>(Level 6) Animate Undead from a necromancer will create 2 undead at a time, and maintain 5 undead (if I understand everything correctly) with each casting. They do not require concentration to maintain, but you do need to reestablish control every 24 hours, so in theory, you lose a bunch of slots to maintain these creatures. And since you have two slots for Animate Undead, you could have 10 undead companions trailing you. </p><p></p><p>I also note the existence of: </p><p>(Level 5) Conjure Animals spell from a wizard. With the wimpy option, you can get eight creatures of 1/4 CR or lower. </p><p>But this requires concentration, and I'm not sure I like counting these creatures because of that. </p><p></p><p></p><p>To optimize for level, I'd probably pick Bard (Lore). At 6th level, I'd choose Animate Undead and Conjure Animals for Magical Secrets. This would cut my maintainable undead group from 10 to 8, but it's a far more "practical" approach. </p><p>I'd be forced to take one level of some wizard to get Find Familiar, along with five levels of Paladin and three levels of Ranger. </p><p></p><p>Total level: 15 </p><p>Total companions: 19</p><p></p><p>Am I missing anything?</p></blockquote><p></p>
[QUOTE="merwins, post: 7105219, member: 6829883"] Just as a thought experiment. I'm trying to determine how many hangers-on a character could have in 5E. Obviously, this would require multi-classing. I have listed the minimum character level to the left of each line. (Level 1) Many spellcasting classes have Find Familiar. Find Familiar doesn't stack. You get one, no matter how many classes offer the spell. (Level 5) Paladin gets Find Steed. (Level 3) Ranger gets a beast companion. (Level 3) Both Bard and Druid have access to the 1st level Animal Friendship (don't hurt me) and the 2nd level Animal Messenger (deliver this) fixed function companion spells. (Level 6) Animate Undead from a necromancer will create 2 undead at a time, and maintain 5 undead (if I understand everything correctly) with each casting. They do not require concentration to maintain, but you do need to reestablish control every 24 hours, so in theory, you lose a bunch of slots to maintain these creatures. And since you have two slots for Animate Undead, you could have 10 undead companions trailing you. I also note the existence of: (Level 5) Conjure Animals spell from a wizard. With the wimpy option, you can get eight creatures of 1/4 CR or lower. But this requires concentration, and I'm not sure I like counting these creatures because of that. To optimize for level, I'd probably pick Bard (Lore). At 6th level, I'd choose Animate Undead and Conjure Animals for Magical Secrets. This would cut my maintainable undead group from 10 to 8, but it's a far more "practical" approach. I'd be forced to take one level of some wizard to get Find Familiar, along with five levels of Paladin and three levels of Ranger. Total level: 15 Total companions: 19 Am I missing anything? [/QUOTE]
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