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<blockquote data-quote="Bill Zebub" data-source="post: 8737616" data-attributes="member: 7031982">Oh, please.&nbsp; There is no &quot;formally correct&quot; in mathematics, there is only correct and incorrect.&nbsp; ((1,2,3,4) 2, 3, 4) is identical to your approach.&nbsp; Just multiply through.One of the most damaging things taught in school is that there is a &quot;correct&quot; way to solve math problems.&nbsp; Or maybe that doing arithmetic is doing math.&nbsp; Or that some people are bad at it.&nbsp; (There are a lot of contenders for that title.)Uh, yeah.&nbsp; Same result.&nbsp; But (D-1)/2D doesn't require 'crunching'. Plug infinity into my formula and you get (infinity - 1) / (2 * infinity) = (drumroll...) 0.5Plug in 1 (for a 1-sided die) and you get 0.Plug in 2 and you get 0.25But the mistake I actually did make is that I shifted back to solving the absolute increase, not the percentage increase. I would have to divide through again by D/2+0.5.&nbsp; So yeah, the % goes down as the die gets larger.EDIT: Doing the last step...on paper not in my head...an equation for the percentage increase is (D-1)/(D^2+D). Which does indeed get smaller as D gets larger (going to zero as D goes to infinity.&nbsp; Which makes sense.)</blockquote>

[QUOTE="Bill Zebub, post: 8737616, member: 7031982"] Oh, please. There is no "formally correct" in mathematics, there is only correct and incorrect. ((1,2,3,4) 2, 3, 4) is identical to your approach. Just multiply through. One of the most damaging things taught in school is that there is a "correct" way to solve math problems. Or maybe that doing arithmetic is doing math. Or that some people are bad at it. (There are a lot of contenders for that title.) Uh, yeah. Same result. But (D-1)/2D doesn't require 'crunching'. Plug infinity into my formula and you get (infinity - 1) / (2 * infinity) = (drumroll...) 0.5 Plug in 1 (for a 1-sided die) and you get 0. Plug in 2 and you get 0.25 But the mistake I actually did make is that I shifted back to solving the absolute increase, not the percentage increase. I would have to divide through again by D/2+0.5. So yeah, the % goes down as the die gets larger. EDIT: Doing the last step...on paper not in my head...an equation for the percentage increase is (D-1)/(D^2+D). Which does indeed get smaller as D gets larger (going to zero as D goes to infinity. Which makes sense.) [/QUOTE]

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