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Flying PC drops bricks from 400' up!
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<blockquote data-quote="Magus_Jerel" data-source="post: 127970" data-attributes="member: 3940"><p>ok - you are dropping an irregular object as a weapon and trying to hit an AREA of approximately 5ft by 5 ft...</p><p>hmmm.</p><p></p><p>The target has an AC of 4. -5 for a dex of "0" and another -1 for being size large.</p><p></p><p>As far as your to hit roll, you take the -4 for non-proficency, but there is another factor. The problem comes with "range increments". By definition - irregular weapons have a range increment of 10 feet, and are limited to a total of five increments. However, given the fact that you are "dropping" this thing - I would remove the limitation on increments.</p><p></p><p>You wind up taking a -2 to hit for each 10 feet dropped - not good for you - especially if the target were mobile.</p><p></p><p>Now - you catch a break, in that you can use the indirect fire rules to determine where the "hole" occurs - you just need to hit A 5x5 square of roof - not a particular sqare. If your roof is big enough - you will hit SOME part of it.</p><p></p><p></p><p></p><p>The damage the object deals is straightforward.</p><p></p><p>You use the falling object rules - on pg 89 of the DMG.</p><p></p><p>Now - presuming you went up to about 200 feet above the TARGET (not the ground mind you) to drop this thing.. it depends on the weight of the brick</p><p></p><p>1-5 lbs = 2d6 dmg</p><p>6-10 lbs = 3d6 dmg</p><p>11-30 lbs = 4d6 dmg</p><p>31-50 lbs = 5d6 dmg</p><p>51-100 lbs = 8d6 dmg (at 210ft)</p><p>100-200 lbs = 10d6</p><p>200+ lbs (at this height) 20d6</p><p></p><p></p><p></p><p>Roof hardness:</p><p>The roof doesn't likely have a hardness between 5 (for wood) and 8 (for stone). You have somewhere between 10 (wood) and 15(for stone) hp per inch of thickness that you need to "punch a hole" in it.</p><p></p><p>Roof thickness:</p><p>Odds are, the roof is somewhere between 1 and 3 inches thick. (I would have to spot cast a d6 - 1 or 2 = 1 inch 3 or 4 is 2 inches and 5 or 6 is 3 inches)</p><p></p><p>thus to generate your "hole in the roof"</p><p></p><p>1 inch wood = 10 dmg</p><p>2 inch wood = 20 dmg</p><p>3 inch wood = 30 dmg</p><p></p><p>1 inch stone = 15 dmg</p><p>2 inch stone = 30 dmg</p><p>3 inch stone = 45 dmg</p><p></p><p>Your roof has a hardness between 5 and 8, and hp total between 10 and 45</p><p></p><p>I would probably rule that you could find something that weighed about 15 lbs - carry it aloft - and drop it. If you hit - you would deal about 4d6 of damage. If the roof is 1 inch thick wood - you will probably get your opening. At 2 inches of wood or more - not going to happen.</p><p></p><p>You will DEFINITELY put a good sized dent in the roof however, and realize that you would need something a bit heavier - or have to go up a bit higher.</p><p></p><p>Note - because this is a collision - the object you are dropping AND the roof would take "damage" appropriately - so the "rock" might shatter into several smaller pieces on impact.</p><p></p><p>You are probably much better of just landing on the roof and cutting/punching a hole in it with an axe, mace, sword (possibly) or hammer. Why bother with "dropping something"?</p></blockquote><p></p>
[QUOTE="Magus_Jerel, post: 127970, member: 3940"] ok - you are dropping an irregular object as a weapon and trying to hit an AREA of approximately 5ft by 5 ft... hmmm. The target has an AC of 4. -5 for a dex of "0" and another -1 for being size large. As far as your to hit roll, you take the -4 for non-proficency, but there is another factor. The problem comes with "range increments". By definition - irregular weapons have a range increment of 10 feet, and are limited to a total of five increments. However, given the fact that you are "dropping" this thing - I would remove the limitation on increments. You wind up taking a -2 to hit for each 10 feet dropped - not good for you - especially if the target were mobile. Now - you catch a break, in that you can use the indirect fire rules to determine where the "hole" occurs - you just need to hit A 5x5 square of roof - not a particular sqare. If your roof is big enough - you will hit SOME part of it. The damage the object deals is straightforward. You use the falling object rules - on pg 89 of the DMG. Now - presuming you went up to about 200 feet above the TARGET (not the ground mind you) to drop this thing.. it depends on the weight of the brick 1-5 lbs = 2d6 dmg 6-10 lbs = 3d6 dmg 11-30 lbs = 4d6 dmg 31-50 lbs = 5d6 dmg 51-100 lbs = 8d6 dmg (at 210ft) 100-200 lbs = 10d6 200+ lbs (at this height) 20d6 Roof hardness: The roof doesn't likely have a hardness between 5 (for wood) and 8 (for stone). You have somewhere between 10 (wood) and 15(for stone) hp per inch of thickness that you need to "punch a hole" in it. Roof thickness: Odds are, the roof is somewhere between 1 and 3 inches thick. (I would have to spot cast a d6 - 1 or 2 = 1 inch 3 or 4 is 2 inches and 5 or 6 is 3 inches) thus to generate your "hole in the roof" 1 inch wood = 10 dmg 2 inch wood = 20 dmg 3 inch wood = 30 dmg 1 inch stone = 15 dmg 2 inch stone = 30 dmg 3 inch stone = 45 dmg Your roof has a hardness between 5 and 8, and hp total between 10 and 45 I would probably rule that you could find something that weighed about 15 lbs - carry it aloft - and drop it. If you hit - you would deal about 4d6 of damage. If the roof is 1 inch thick wood - you will probably get your opening. At 2 inches of wood or more - not going to happen. You will DEFINITELY put a good sized dent in the roof however, and realize that you would need something a bit heavier - or have to go up a bit higher. Note - because this is a collision - the object you are dropping AND the roof would take "damage" appropriately - so the "rock" might shatter into several smaller pieces on impact. You are probably much better of just landing on the roof and cutting/punching a hole in it with an axe, mace, sword (possibly) or hammer. Why bother with "dropping something"? [/QUOTE]
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