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<blockquote data-quote="DMScott" data-source="post: 1775161" data-attributes="member: 11734">Ah, OK. I believe when the book says &quot;Compute an encounter level for the reward using the CRs from all the associated encounters&quot;, they mean to use the &quot;Determining Encounter Levels&quot; section on pgs 205-207, rather than just adding them together. In particular, the &quot;Total Challenge Rating&quot; section starting at the bottom of page 206 shows how multiple CRs (and ELs) accumulate. So the six EL 4 encounters, for example, accumulate to EL 10 rather than EL 24.You could add those up any of a number of ways, and probably get slightly different results. Since table 7-6 groups &quot;6 or more&quot; into a single category, what you might want to do is average the first six and calculate EL, then the next six, then the last five. Then average those together for the final result. By doing that I get:1st 6: (7+1+2+4+2+4)/6 is an average EL of 3 (since you round down), six EL 3 encounters are EL 9.2nd 6: (1+3+4+4+1+4)/6 is an average EL of 2, six EL 2 encounters are EL 8.Final group of 5: (3+6+8+4+9)/5 is an average EL of 6, six EL 6 encounters are EL 12.I would be inclined to give awards based on these three sets, I think - if you average them down to a single value, it also comes out EL 12, which might not seem fair. Whichever way you go, you can then go back to 204 and finish the calculations. It might be an interesting exercise to calculate for each encounter separately and see how that compares to the totalling ELs method.</blockquote>

[QUOTE="DMScott, post: 1775161, member: 11734"] Ah, OK. I believe when the book says "Compute an encounter level for the reward using the CRs from all the associated encounters", they mean to use the "Determining Encounter Levels" section on pgs 205-207, rather than just adding them together. In particular, the "Total Challenge Rating" section starting at the bottom of page 206 shows how multiple CRs (and ELs) accumulate. So the six EL 4 encounters, for example, accumulate to EL 10 rather than EL 24. You could add those up any of a number of ways, and probably get slightly different results. Since table 7-6 groups "6 or more" into a single category, what you might want to do is average the first six and calculate EL, then the next six, then the last five. Then average those together for the final result. By doing that I get: 1st 6: (7+1+2+4+2+4)/6 is an average EL of 3 (since you round down), six EL 3 encounters are EL 9. 2nd 6: (1+3+4+4+1+4)/6 is an average EL of 2, six EL 2 encounters are EL 8. Final group of 5: (3+6+8+4+9)/5 is an average EL of 6, six EL 6 encounters are EL 12. I would be inclined to give awards based on these three sets, I think - if you average them down to a single value, it also comes out EL 12, which might not seem fair. Whichever way you go, you can then go back to 204 and finish the calculations. It might be an interesting exercise to calculate for each encounter separately and see how that compares to the totalling ELs method. [/QUOTE]

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