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Hard sci-fi question: rotational artificial gravity space station
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<blockquote data-quote="Umbran" data-source="post: 6877664" data-attributes="member: 177"><p>How do you want it "squashed"? Here's a note: the sphere is in many ways a bad idea. A cylinder is a better bet. The centrifugal force felt depends upon the distance from the axis of rotation. So, if you spin the thing so you feel a full G at the equator, anywhere "north" or "south) of the equator has lower force. If you want more surface to be at 1 G, use a cylinder.</p><p></p><p></p><p></p><p></p><p>It depends upon the size of the sphere. If your change in elevation is negligible compared to the radius, you won't feel much difference. If you are talking about a 100 meter tall building in a 1 KM radius sphere, you'll notice it.</p><p></p><p></p><p></p><p>If you can build the sphere in the first place, building materials are probably not your biggest problem. Remember that we *are* talking about cfreating a very large structure *in space* already.</p><p></p><p> </p><p></p><p>Well, be careful there. When we are talking about deflection due to spin, it is actually that the object is moving straight, and the Earth is spinning under it! </p><p></p><p></p><p></p><p>Again, the difference will depend in general on the size of the sphere - the larger the sphere, the less noticeable the effect will be. </p><p></p><p>In general, if you are throwing directly along or against the spin (so "east" or "west" - or what you'd probably want to call "spinward" and "anti-spinward"), what you'll see is your throw fall short or go farther than you'd expect. If you throw north or south, you'll see it go wide to the left or right some. </p><p></p><p></p><p></p><p>Not really in a position to work out the exact numbers at the moment, I'm afraid. Perhaps later.</p></blockquote><p></p>
[QUOTE="Umbran, post: 6877664, member: 177"] How do you want it "squashed"? Here's a note: the sphere is in many ways a bad idea. A cylinder is a better bet. The centrifugal force felt depends upon the distance from the axis of rotation. So, if you spin the thing so you feel a full G at the equator, anywhere "north" or "south) of the equator has lower force. If you want more surface to be at 1 G, use a cylinder. It depends upon the size of the sphere. If your change in elevation is negligible compared to the radius, you won't feel much difference. If you are talking about a 100 meter tall building in a 1 KM radius sphere, you'll notice it. If you can build the sphere in the first place, building materials are probably not your biggest problem. Remember that we *are* talking about cfreating a very large structure *in space* already. Well, be careful there. When we are talking about deflection due to spin, it is actually that the object is moving straight, and the Earth is spinning under it! Again, the difference will depend in general on the size of the sphere - the larger the sphere, the less noticeable the effect will be. In general, if you are throwing directly along or against the spin (so "east" or "west" - or what you'd probably want to call "spinward" and "anti-spinward"), what you'll see is your throw fall short or go farther than you'd expect. If you throw north or south, you'll see it go wide to the left or right some. Not really in a position to work out the exact numbers at the moment, I'm afraid. Perhaps later. [/QUOTE]
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