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<blockquote data-quote="Nail" data-source="post: 1348533" data-attributes="member: 224">Huh.&nbsp; A bit of a flame war, eh?&nbsp; That's too bad.Anyway, back On Topic:&nbsp;&nbsp; It looks like IRS is probably balanced in a typical campaign, given the length of the feat chain and the increase in average damage over Rapid Shot.&nbsp; Still, it's a close thing, and I wouldn't blame anyone for removing IRS from their game.&nbsp; In a campaign with a lot of &quot;mooks&quot; (# of PCs &lt;&lt; # of monsters), this feat is probably too good.&nbsp; In a campaign with lots of &quot;boss monsters&quot; (# of PCs &gt;&gt; # of Monsters), it's just an &quot;okay&quot; feat.Note: The # of Monsters per PC is far more important than hp in the analysis.&nbsp; Think about that.&nbsp; Remember, in D&amp;D, we assume that APL = EL, much of the time.&nbsp; So hp of monsters scale with APL.&nbsp; (APL = Average Party Level)Actually, the equation I gave above handles both the &quot;always miss on a 1&quot; and &quot;always hit on a 20&quot;.&nbsp; At least...I'm pretty darn sure it does.&nbsp; I'd be willing to hear proof otherwise.Here it is again:P = Min[Max(21 - AC + Atk, 1),19]/20where:
<ul>
<li data-xf-list-type="ul">&quot;P&quot; = probability to hit with an attack</li>
<li data-xf-list-type="ul">&quot;AC&quot; = opponent's AC</li>
<li data-xf-list-type="ul">&quot;Atk&quot; = attacker's total attack bonus (BAB, Str, Magic, Iterative Attack penalty, etc), and </li>
<li data-xf-list-type="ul">&quot;Min&quot; &amp; &quot;Max&quot; = are functions within the Excel spreadsheet, finding either the smaller (Min) or larger (Max) of two numbers.</li>
</ul>Just take that &quot;P&quot; and multiply it by your expected average damage per attack, and you've got it.&nbsp; Don't forget the criticals.&nbsp; [1 + Pc(M-1)] , where:
<ul>
<li data-xf-list-type="ul">&quot;Pc&quot; = percent chance to critcal (typically 5 - 10%), and</li>
<li data-xf-list-type="ul"> &quot;M&quot; = critical multiplier</li>
</ul>I'm still working on that.&nbsp; At higher threat ranges, my simple equation above breaks down.&nbsp;&nbsp; Surely someone else has already derived the formula?&nbsp; Here's your chance to show me up!&nbsp;&nbsp; <img src="https://cdn.jsdelivr.net/joypixels/assets/8.0/png/unicode/64/1f609.png" class="smilie smilie--emoji" loading="lazy" width="64" height="64" alt=";)" title="Wink&nbsp; &nbsp; ;)"&nbsp; data-smilie="2"data-shortname=";)" /></blockquote>

[QUOTE="Nail, post: 1348533, member: 224"] Huh. A bit of a flame war, eh? That's too bad. Anyway, back On Topic: It looks like IRS is [u]probably[/u] balanced [i]in a typical campaign[/i], given the length of the feat chain and the increase in average damage over [i]Rapid Shot[/i]. Still, it's a close thing, and I wouldn't blame anyone for removing IRS from their game. In a campaign with a lot of "mooks" (# of PCs << # of monsters), this feat is probably [b]too[/b] good. In a campaign with lots of "boss monsters" (# of PCs >> # of Monsters), it's just an "okay" feat. Note: The # of Monsters per PC is far more important than hp in the analysis. Think about that. Remember, in D&D, we assume that APL = EL, much of the time. So hp of monsters scale with APL. (APL = Average Party Level) Actually, the equation I gave above handles both the "always miss on a 1" [i]and[/i] "always hit on a 20". At least...I'm pretty darn sure it does. I'd be willing to hear proof otherwise. Here it is again: P = Min[Max(21 - AC + Atk, 1),19]/20 where:[list][*]"P" = probability to hit with an attack [*]"AC" = opponent's AC [*]"Atk" = attacker's total attack bonus (BAB, Str, Magic, Iterative Attack penalty, etc), and [*]"Min" & "Max" = are functions within the Excel spreadsheet, finding either the smaller (Min) or larger (Max) of two numbers.[/list] Just take that "P" and multiply it by your expected average damage per attack, and you've got it. Don't forget the criticals. [1 + Pc(M-1)] , where:[list][*]"Pc" = percent chance to critcal (typically 5 - 10%), and [*] "M" = critical multiplier[/list] I'm still working on that. At higher threat ranges, my simple equation above breaks down. Surely someone else has already derived the formula? Here's your chance to show me up! ;) [/QUOTE]

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