Upgrade your account to a Community Supporter account and remove most of the site ads.

Reply to thread

Message: <blockquote data-quote="TwoHeadsBarking" data-source="post: 5724435" data-attributes="member: 82251">Warning, it is too early in the morning for me to be entirely serious.I would say you can't increase the size past one square.  I have two reasons for thinking this:<ol> <li data-xf-list-type="ol">It makes the calculations much easier, which is to say it removes the need for them.</li> <li data-xf-list-type="ol">There is no difference between a square and a circle in 4e.</li> </ol>Take a look at a battle map.  Or any grid, really.  Imagine a 3x3 area, the result of a close burst 1.  For game purposes, all points on the outside of the burst are equidistant from the center.  That is pretty much the definition of a circle.  So what we thought was a square is actually a circle.  Well, technically it's a disc.  The point is that your 5 ft by 5 ft square is actually (or perhaps also) a circle with diameter 5 ft, which means you don't have any extra area to work with.The implications of this, by the way, get hilariously ugly.  You have adjacent circles that share entire edges, and you can place four of them next to each other to create a bigger circle.  Previously straight hallways twist and buckle as their shapes change depending on where you're standing.  Reality itself rends and tears, all because it doesn't cost any extra movement to go diagonally.Also, your calculations aren't quite right.  When you converted from feet to meters, you went from 25 ft to 7.62 m.  But what you needed to do was go from 25 square feet to 2.32 square meters.  If the maximum area of the image's "footprint" is 25 square feet, then we can find the maximum radius of the footprint, if we choose to believe that circles and squares are different:<ul> <li data-xf-list-type="ul">Circular area = 25 square feet</li> <li data-xf-list-type="ul">(pi)r^2=25 square feet</li> <li data-xf-list-type="ul">r^2=7.96 square feet</li> <li data-xf-list-type="ul">r=2.82 feet</li> </ul>In meters, the radius is 0.86 m.  If we switch back to feet, the diameter of the semisphere is 5.64 ft, which means the image would go past its original boundaries by .32 ft, or 3.84 inches, on each side.  That is probably not worth the trouble.  You get a few more feet if you choose to work with volume instead of footprint area, but I'll leave those calculations as an exercise to the reader.</blockquote>

Verification