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<blockquote data-quote="Cheiromancer" data-source="post: 1646941" data-attributes="member: 141"><p>Also on that thread I've floated a proposal that the xp be related to the square of the party's levels, not just the square of the CR. I.e., you square the levels of the party members and add them up. Call that Y. Then the xp per character level is</p><p></p><p>xp = (CR^2)*300/Y</p><p></p><p>It's a generalization of the formula we were using for the total xp of a 4 person group, all of whom were the same level:</p><p></p><p>total xp = (CR^2)*300/n</p><p></p><p>where n is the level of the group. Divide by the total number of levels to determine the xp/character level. If you divide by 4n, the denominator looks a lot like the sum of the squares of the CRs of the characters, which is nicely parallel to the CR^2 in the numerator (that, of course, is a sum when there are multiple opponents.)</p><p></p><p>I think the Y formula is kinda elegant. I wish there were an equally elegant way of helping characters catch up in xp, but I don't know of any. The power factor method that Anubis (replace n by the product of the individual's character level and the number of people in the group) doesn't seem as pretty to me.</p></blockquote><p></p>
[QUOTE="Cheiromancer, post: 1646941, member: 141"] Also on that thread I've floated a proposal that the xp be related to the square of the party's levels, not just the square of the CR. I.e., you square the levels of the party members and add them up. Call that Y. Then the xp per character level is xp = (CR^2)*300/Y It's a generalization of the formula we were using for the total xp of a 4 person group, all of whom were the same level: total xp = (CR^2)*300/n where n is the level of the group. Divide by the total number of levels to determine the xp/character level. If you divide by 4n, the denominator looks a lot like the sum of the squares of the CRs of the characters, which is nicely parallel to the CR^2 in the numerator (that, of course, is a sum when there are multiple opponents.) I think the Y formula is kinda elegant. I wish there were an equally elegant way of helping characters catch up in xp, but I don't know of any. The power factor method that Anubis (replace n by the product of the individual's character level and the number of people in the group) doesn't seem as pretty to me. [/QUOTE]
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