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<blockquote data-quote="Kavon" data-source="post: 1647265" data-attributes="member: 9822"><p>Ok, so if I understand you correctly...</p><p></p><p>Let's say we have a party of 4, with one level 6 (36), two level 5 (25*2), and one level 4 (16) characters (Y=102).</p><p>They win a fight with a CR of 5, which is 7500 raw XP.</p><p>7500 / 1200 = 73.53 (do you round down for this? I'll assume it does for the following, since it's irrelevent for the example).</p><p></p><p>The Lvl 6 character gets 438 XP, which is about 13.7 encounters to level up.</p><p>The two Lvl 5 characters each get 365 XP, which is also about 13.7 encounters to level up.</p><p>The Lvl 4 character gets 292 XP, which is also about 13.7 encounters to level up.</p><p></p><p>It will take the members of the party an equal time to level up, irrelevent of what level they have. So, the level 4 character will always remain 1 level behind on the level 5 characters, who will always be 1 level behind on the level 6 character.</p><p></p><p>Did I get it right?</p><p></p><p>If so, I don't really see how this is an improvement on Anubis' formula, since the characters don't even out in the long run.</p><p></p><p>Edit: wow, how could I not see that newer reply? *pokes browser*</p><p></p><p>Hmm... That side of the system (talking about the <em>the Lord of the Rings</em> orientated explanation) does sound good, but the fact that advancement is equal for each party member, irrelevant of level difference, does make it sound less good. The Ranger needs to fight the same fight (a little under) 7 times to go to level 21, and the hobbits will go to level 2 at the exact same time. When the Ranger hits level 22, the hobbits hit level 3, etc...</p><p></p><p>Edit 2: Hmm... Though, after compairing the two results, Anubis' formula seems to hold the other extreme, with the Ranger needing a little over 27 such fights to hit level 21 (solo: a little under 7), and the hobbits each gain enough XP to rocket them into the high end of level 4...</p></blockquote><p></p>
[QUOTE="Kavon, post: 1647265, member: 9822"] Ok, so if I understand you correctly... Let's say we have a party of 4, with one level 6 (36), two level 5 (25*2), and one level 4 (16) characters (Y=102). They win a fight with a CR of 5, which is 7500 raw XP. 7500 / 1200 = 73.53 (do you round down for this? I'll assume it does for the following, since it's irrelevent for the example). The Lvl 6 character gets 438 XP, which is about 13.7 encounters to level up. The two Lvl 5 characters each get 365 XP, which is also about 13.7 encounters to level up. The Lvl 4 character gets 292 XP, which is also about 13.7 encounters to level up. It will take the members of the party an equal time to level up, irrelevent of what level they have. So, the level 4 character will always remain 1 level behind on the level 5 characters, who will always be 1 level behind on the level 6 character. Did I get it right? If so, I don't really see how this is an improvement on Anubis' formula, since the characters don't even out in the long run. Edit: wow, how could I not see that newer reply? *pokes browser* Hmm... That side of the system (talking about the [i]the Lord of the Rings[/i] orientated explanation) does sound good, but the fact that advancement is equal for each party member, irrelevant of level difference, does make it sound less good. The Ranger needs to fight the same fight (a little under) 7 times to go to level 21, and the hobbits will go to level 2 at the exact same time. When the Ranger hits level 22, the hobbits hit level 3, etc... Edit 2: Hmm... Though, after compairing the two results, Anubis' formula seems to hold the other extreme, with the Ranger needing a little over 27 such fights to hit level 21 (solo: a little under 7), and the hobbits each gain enough XP to rocket them into the high end of level 4... [/QUOTE]
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