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<blockquote data-quote="Dausuul" data-source="post: 6432081" data-attributes="member: 58197">Breaking it down:Main weapon attack:<ul>
<li data-xf-list-type="ul">65% normal hit for 1d6+3 (6.5) damage. DPR: 4.225</li>
<li data-xf-list-type="ul">5% crit for 2d6+3 (10) damage. DPR: 0.5</li>
</ul>Off-hand attack:<ul>
<li data-xf-list-type="ul">65% normal hit for 1d6 (3.5) damage. DPR: 2.275</li>
<li data-xf-list-type="ul">5% crit for 2d6 (7) damage. DPR: 0.35</li>
</ul>Sneak Attack*:<ul>
<li data-xf-list-type="ul">84.5% normal hit for 1d6 (3.5) damage. DPR: 2.9575</li>
<li data-xf-list-type="ul">6.5% crit for 2d6 (7) damage. DPR: 0.455</li>
</ul>I get a total DPR of 10.7625 (did I miss something?). Note that when the rogue reaches level 3, the Sneak Attack contribution doubles, so her DPR shoots up to 14.175.[size=-2]*Assume that the rogue will expend Sneak Attack on the first attack that hits; thus, if the first attack is a regular hit and the second is a crit, the rogue does normal Sneak Attack damage rather than doubled. So the chance for normal sneak attack dice is equal to 0.65 (hit with the first attack) + 0.3 x 0.65 (miss with the first attack, normal hit with the second). The chance for double sneak attack dice is 0.05 (crit with the first attack) + 0.3 x 0.05 (miss with the first attack, crit with the second).[/size]</blockquote>

[QUOTE="Dausuul, post: 6432081, member: 58197"] Breaking it down: Main weapon attack: [list][*]65% normal hit for 1d6+3 (6.5) damage. DPR: 4.225 [*]5% crit for 2d6+3 (10) damage. DPR: 0.5[/list] Off-hand attack: [list][*]65% normal hit for 1d6 (3.5) damage. DPR: 2.275 [*]5% crit for 2d6 (7) damage. DPR: 0.35[/list] Sneak Attack*: [list][*]84.5% normal hit for 1d6 (3.5) damage. DPR: 2.9575 [*]6.5% crit for 2d6 (7) damage. DPR: 0.455[/list] I get a total DPR of 10.7625 (did I miss something?). Note that when the rogue reaches level 3, the Sneak Attack contribution doubles, so her DPR shoots up to 14.175. [size=-2]*Assume that the rogue will expend Sneak Attack on the first attack that hits; thus, if the first attack is a regular hit and the second is a crit, the rogue does normal Sneak Attack damage rather than doubled. So the chance for normal sneak attack dice is equal to 0.65 (hit with the first attack) + 0.3 x 0.65 (miss with the first attack, normal hit with the second). The chance for double sneak attack dice is 0.05 (crit with the first attack) + 0.3 x 0.05 (miss with the first attack, crit with the second).[/size] [/QUOTE]

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