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Message: <blockquote data-quote="Technik4" data-source="post: 514375" data-attributes="member: 7211">Seems overpowered to me. You can get in at 5th level (the optimal level for a wizard to take a prestige class as he just acquired a meta feat and wont get another one for 5 more levels). I would raise the entry things so you can't join till 5th level spells (9th level).Ok, I just want to point out the differences of going to your prestige class vs staying a wizard. In 10 levels the wizard will have gained some familiar abilities and 2 metamagic feats. In 10 levels of your prestige class, all his chosen energy spells deal +4 damager "per die". Example time! Ok, 15th level wizard uses 5th level slot to cast an empowered fireball. 10d6 (+1/2 10d6) damage, reflex save at x. Now 5Wiz/10MoE casts a fireball (using a 3rd level slot). 10d6+40 damage at reflex save x+3. Lets say we rolled average for those d6s, 30 damage each. The 15th level wizard who used empowered and a 5th level slot does 45 damage. The 5Wiz/10MoE uses a 3rd level slot and does 70 damage.Ok, so I think we've nailed down whats incredibly overpowered about this prc. Now, criticism. Obviously +1 damage per die is wayyy overpowered. I would even say +1 damage up to the maximum the die can do is overpowered (ie if you roll a 1 it becomes a 2, roll a 6 its still 6) at +4 for 10th level prc. Now if at level 10 you get +1 damage per die up to max, thats reasonable. In the above example, the 5Wiz/10MoE would have done an average of 40 instead of an average of 30, still less than the wizard (who empowered his), but its got some extra oomph.Other than that, I think you should lower the bonuses to penetration checks and DC checks to a max of +2. Also, as an added negative, the directly opposing energy that you chose acts as if it were empowered whenever you take damage from it. Directly opposing elements is in Tome and Blood. Thats a more significant detractor than making the spells that ARENT your energy weaker. Especially when you have energy substitution.Technik</blockquote>

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