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[Math question] Finding the Size of a shadow
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<blockquote data-quote="Storminator" data-source="post: 901004" data-attributes="member: 305"><p>Utrecht is correct. The right angle in your right triangle is between the verrtical object casting the shadow and the ground. If the ground isn't level, or the object isn't vertical, the angle isn't right, an neither is the triangle.</p><p></p><p>If the casting object is height H, the angle between the light source and vertical is A, and the angle between the ground and the object is B, the shadow length L is:</p><p></p><p>L = H *sin(A)/sin(180-A-B)</p><p></p><p>Note that when both A = B = 90, sin(180-A-B)=0 and shadow length is infinite.</p><p></p><p>Determining the angle the sun makes with the vertical as a function of time of day, latitude, and time of year is left as an exercise for the reader, as are corrections for curvature of the earth. <img src="https://cdn.jsdelivr.net/joypixels/assets/8.0/png/unicode/64/1f609.png" class="smilie smilie--emoji" loading="lazy" width="64" height="64" alt=";)" title="Wink ;)" data-smilie="2"data-shortname=";)" /></p><p></p><p>PS</p></blockquote><p></p>
[QUOTE="Storminator, post: 901004, member: 305"] Utrecht is correct. The right angle in your right triangle is between the verrtical object casting the shadow and the ground. If the ground isn't level, or the object isn't vertical, the angle isn't right, an neither is the triangle. If the casting object is height H, the angle between the light source and vertical is A, and the angle between the ground and the object is B, the shadow length L is: L = H *sin(A)/sin(180-A-B) Note that when both A = B = 90, sin(180-A-B)=0 and shadow length is infinite. Determining the angle the sun makes with the vertical as a function of time of day, latitude, and time of year is left as an exercise for the reader, as are corrections for curvature of the earth. ;) PS [/QUOTE]
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[Math question] Finding the Size of a shadow
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