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Message: <blockquote data-quote="reanjr" data-source="post: 1923428" data-attributes="member: 20740">Say you've got 20 guards.  Most likely one of them will roll a 20.  The theory is that one would roll a 1, a second would roll a 2, and so on.  So, in that situation, I would give them a "roll" of 20.  For lesser amount, lower this value by 1 for every two fewer guards.  So 18 guards would roll 2-19.  Using the 19 value would give you a result.12 guards would roll 5-16.This is how I would do Taking 10 in a group.[edit<img src="http://www.enworld.org/forum/images/smilies/devious.png"  class="smilie" loading="lazy" alt=":]" title="Devious    :]" data-shortname=":]" /> Additional guidelines for multiple effects stacking:Just in case someone likes this method, here are some methods for determining how many successes occur.  Note, this is not an exact mathematical method, but it gives usable and reasonable results.Start at 10.  For each individual beyond the first, add 1.  Every time, you reach the DC of the action, you have one success and you go back down to 10 and keep counting.And finally, for large groups making attacks (a volley of arrows, for instance) add +1 to the BAB for each individual beyond the first.  So, a unit of 20 archers, each with a BAB of +4 could be treated as a single individual with a BAB of +23/+18/+13/+8/+3.  You only have to roll 5 attacks now instead of 20.  This is taken from Salt and Sea Dogs.If you need to extend this (for instance with 100 archers) you can repeat this as if you had a number of individuals with a BAB equal to the average of the multiple attacks.  For instance (I would suggest doing it until you have a BAB of +30 or less, to maintain as much accuracy as possible while giving you as little work as possible), the average of the +23/+18/+13/+8/+3 attack routine is +13.  If you had 5 combatants (5 attacks) at +13, you would treat it as a single combatant at +17.  So your unit of archers attacks at +17/+12/+7/+2.  This is most accurate with hig ACs.</blockquote>

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