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<blockquote data-quote="Vinyafod" data-source="post: 507091" data-attributes="member: 6206">For such things it is best to write down the chances/ combinations of possible die rolls and simply start counting then:possible outcomes of 2d10 (not summed up!! but percentile roll)[code]&nbsp; &nbsp; 0&nbsp; &nbsp; 1&nbsp; &nbsp; 2&nbsp; &nbsp; 3&nbsp; &nbsp; 4&nbsp; &nbsp; 5&nbsp; &nbsp; 6&nbsp; &nbsp; 7&nbsp; &nbsp; 8&nbsp; &nbsp; 9 0&nbsp;&nbsp; 00&nbsp;&nbsp; [b][color=red]01&nbsp;&nbsp; 02&nbsp;&nbsp; 03&nbsp;&nbsp; 04&nbsp;&nbsp; 05&nbsp;&nbsp; 06&nbsp;&nbsp; 07&nbsp;&nbsp; 08&nbsp;&nbsp; 09[/color]1[color=red]&nbsp;&nbsp; 10&nbsp;&nbsp; 11&nbsp;&nbsp; 12&nbsp;&nbsp; 12&nbsp;&nbsp; 14&nbsp;&nbsp; 15&nbsp;&nbsp; 16&nbsp;&nbsp; 17&nbsp;&nbsp; 18&nbsp;&nbsp; 19[/color]2[color=red]&nbsp;&nbsp; 20&nbsp;&nbsp; 21&nbsp;&nbsp; 22&nbsp;&nbsp; 23&nbsp;&nbsp; 24&nbsp;&nbsp; 25[/b][/color]&nbsp;&nbsp; 26&nbsp;&nbsp; 27&nbsp;&nbsp; 28&nbsp;&nbsp; 29 3&nbsp;&nbsp; 30&nbsp;&nbsp; 31&nbsp;&nbsp; 32&nbsp;&nbsp; 33&nbsp;&nbsp; 34&nbsp;&nbsp; 35&nbsp;&nbsp; 36&nbsp;&nbsp; 37&nbsp;&nbsp; 38&nbsp;&nbsp; 384&nbsp;&nbsp; 40&nbsp;&nbsp; 41&nbsp;&nbsp; 42&nbsp;&nbsp; 43&nbsp;&nbsp; 44&nbsp;&nbsp; 45&nbsp;&nbsp; 46&nbsp;&nbsp; 47&nbsp;&nbsp; 48&nbsp;&nbsp; 49 5&nbsp;&nbsp; 50&nbsp;&nbsp; 51&nbsp;&nbsp; 52&nbsp;&nbsp; 53&nbsp;&nbsp; 54&nbsp;&nbsp; 55&nbsp;&nbsp; 56&nbsp;&nbsp; 57&nbsp;&nbsp; 58&nbsp;&nbsp; 596&nbsp;&nbsp; 60&nbsp;&nbsp; 61&nbsp;&nbsp; 62&nbsp;&nbsp; 63&nbsp;&nbsp; 64&nbsp;&nbsp; 65&nbsp;&nbsp; 66&nbsp;&nbsp; 67&nbsp;&nbsp; 68&nbsp;&nbsp; 697&nbsp;&nbsp; 70&nbsp;&nbsp; 71&nbsp;&nbsp; 72&nbsp;&nbsp; 73&nbsp;&nbsp; 74&nbsp;&nbsp; 75&nbsp;&nbsp; 76&nbsp;&nbsp; 77&nbsp;&nbsp; 78&nbsp;&nbsp; 798&nbsp;&nbsp; 80&nbsp;&nbsp; 81&nbsp;&nbsp; 82&nbsp;&nbsp; 83&nbsp;&nbsp; 84&nbsp;&nbsp; 85&nbsp;&nbsp; 86&nbsp;&nbsp; 87&nbsp;&nbsp; 88&nbsp;&nbsp; 899&nbsp;&nbsp; 90&nbsp;&nbsp; 91&nbsp;&nbsp; 92&nbsp;&nbsp; 93&nbsp;&nbsp; 94&nbsp;&nbsp; 95&nbsp;&nbsp; 96&nbsp;&nbsp; 97&nbsp;&nbsp; 98&nbsp;&nbsp; 99[/code]We have a hundred different combinations here. 25 of those gives scores of 25 or lower. 25 out of 100&nbsp; =25/100 = 1/4 = 25%d4:1234We have 4 &quot;combinations&quot;. One of those gives a 1. 1 out of 4 = 1/4 = 25% That is absolutely correct and nothing to argue about. Chances are exactly the same. Believe it or not. if that won't convice you, nothing will.To take the approach you tried in your last post:Assuming numbers 1 to 25 are not wanted...The first die always displays the 10-digit, the second the 1-digit.First roll = 0&nbsp; (chance to happen: 10%), second roll must be 0 in order to succeed (chance to happen: 10%) -&gt; 0.1*0,1=0.01 -&gt; 1% chance to succed on a first roll of a 0First die shows a 1 (10% chance), nothing can save you now -&gt; plain 0% chance to suceed -&gt; 0%First die shows a 2 (10% chance), 6 to 9 will succeed (40% chance) -&gt; 0.1*0.4=0.04 -&gt; 4% chance to succeed on a first roll of a 2First die show 3 to 9 (70% chance), all those will automatically succeed -&gt; plain 70% chance1% + 4% + 70% = 75%&nbsp; 3 out of 4 succeed 75% chance to succeed.Thats the maths whith which you calculate it!Hope that will convince you. <img src="https://cdn.jsdelivr.net/joypixels/assets/8.0/png/unicode/64/1f642.png" class="smilie smilie--emoji" loading="lazy" width="64" height="64" alt=":)" title="Smile&nbsp; &nbsp; :)"&nbsp; data-smilie="1"data-shortname=":)" /></blockquote>

[QUOTE="Vinyafod, post: 507091, member: 6206"] For such things it is best to write down the chances/ combinations of possible die rolls and simply start counting then: possible outcomes of 2d10 (not summed up!! but percentile roll) [code] 0 1 2 3 4 5 6 7 8 9 0 00 [b][color=red]01 02 03 04 05 06 07 08 09[/color] 1[color=red] 10 11 12 12 14 15 16 17 18 19[/color] 2[color=red] 20 21 22 23 24 25[/b][/color] 26 27 28 29 3 30 31 32 33 34 35 36 37 38 38 4 40 41 42 43 44 45 46 47 48 49 5 50 51 52 53 54 55 56 57 58 59 6 60 61 62 63 64 65 66 67 68 69 7 70 71 72 73 74 75 76 77 78 79 8 80 81 82 83 84 85 86 87 88 89 9 90 91 92 93 94 95 96 97 98 99[/code] We have a hundred different combinations here. 25 of those gives scores of 25 or lower. 25 out of 100 =25/100 = 1/4 = 25% d4: 1 2 3 4 We have 4 "combinations". One of those gives a 1. 1 out of 4 = 1/4 = 25% That is absolutely correct and nothing to argue about. Chances are [b]exactly[/b] the same. Believe it or not. if that won't convice you, nothing will. To take the approach you tried in your last post: Assuming numbers 1 to 25 are not wanted... The first die always displays the 10-digit, the second the 1-digit. First roll = 0 (chance to happen: 10%), second roll must be 0 in order to succeed (chance to happen: 10%) -> 0.1*0,1=0.01 -> 1% chance to succed on a first roll of a 0 First die shows a 1 (10% chance), nothing can save you now -> plain 0% chance to suceed -> 0% First die shows a 2 (10% chance), 6 to 9 will succeed (40% chance) -> 0.1*0.4=0.04 -> 4% chance to succeed on a first roll of a 2 First die show 3 to 9 (70% chance), all those will automatically succeed -> plain 70% chance 1% + 4% + 70% = 75% 3 out of 4 succeed 75% chance to succeed. Thats the maths whith which you calculate it! Hope that will convince you. :) [/QUOTE]

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