Sir Brennen
Legend
So, I'm tinkering with a d10 die mechanic. In it, multiple dice are rolled, and any die with a roll over a given value is discarded. The remaining dice are summed.
For example, 5d10 are rolled with values of 6, 5, 9, 5 and 9. The target value is 7. The 9's are therefore discarded, for a total of 16 for the remainder.
What I'm looking for is, how would you compute the average final sum for X d10 dice vs. Target Number Y. X could be any whole value, but for practical purposes, will rarely exceed 10, and more often be in the 2 to 5 range. Y can be any whole value between 1 and 10.
I took a stab at it, and came up with this:
Avg = (Y + 1) ÷ 2)) * (Y ÷ 10) * X
So, for Target Number of 10 on 4 dice, it would be 5.5 * 1 * 4, or 22 (the normal average of 4d10)
For a Target Number of of 7 on 4 dice, it would be 4 * 0.7 * 4, or 11.2 So a target number of 7 will yield an average roll approximately 51% of a target number 10.
Can anyone verify I'm figuring this correctly, or want to shed any deeper statistical analysis on this mechanic?
For example, 5d10 are rolled with values of 6, 5, 9, 5 and 9. The target value is 7. The 9's are therefore discarded, for a total of 16 for the remainder.
What I'm looking for is, how would you compute the average final sum for X d10 dice vs. Target Number Y. X could be any whole value, but for practical purposes, will rarely exceed 10, and more often be in the 2 to 5 range. Y can be any whole value between 1 and 10.
I took a stab at it, and came up with this:
Avg = (Y + 1) ÷ 2)) * (Y ÷ 10) * X
So, for Target Number of 10 on 4 dice, it would be 5.5 * 1 * 4, or 22 (the normal average of 4d10)
For a Target Number of of 7 on 4 dice, it would be 4 * 0.7 * 4, or 11.2 So a target number of 7 will yield an average roll approximately 51% of a target number 10.
Can anyone verify I'm figuring this correctly, or want to shed any deeper statistical analysis on this mechanic?