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Need Math Help on mechanic
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<blockquote data-quote="Sir Brennen" data-source="post: 3408627" data-attributes="member: 553"><p>So, I'm tinkering with a d10 die mechanic. In it, multiple dice are rolled, and any die with a roll over a given value is discarded. The remaining dice are summed. </p><p></p><p>For example, 5d10 are rolled with values of 6, 5, 9, 5 and 9. The target value is 7. The 9's are therefore discarded, for a total of 16 for the remainder.</p><p></p><p>What I'm looking for is, how would you compute the average final sum for <em>X</em> d10 dice vs. Target Number <em>Y</em>. X could be any whole value, but for practical purposes, will rarely exceed 10, and more often be in the 2 to 5 range. Y can be any whole value between 1 and 10.</p><p></p><p>I took a stab at it, and came up with this:</p><p></p><p><strong>Avg = (Y + 1) ÷ 2)) * (Y ÷ 10) * X</strong></p><p></p><p>So, for Target Number of 10 on 4 dice, it would be 5.5 * 1 * 4, or 22 (the normal average of 4d10)</p><p></p><p>For a Target Number of of 7 on 4 dice, it would be 4 * 0.7 * 4, or 11.2 So a target number of 7 will yield an average roll approximately 51% of a target number 10.</p><p></p><p>Can anyone verify I'm figuring this correctly, or want to shed any deeper statistical analysis on this mechanic?</p></blockquote><p></p>
[QUOTE="Sir Brennen, post: 3408627, member: 553"] So, I'm tinkering with a d10 die mechanic. In it, multiple dice are rolled, and any die with a roll over a given value is discarded. The remaining dice are summed. For example, 5d10 are rolled with values of 6, 5, 9, 5 and 9. The target value is 7. The 9's are therefore discarded, for a total of 16 for the remainder. What I'm looking for is, how would you compute the average final sum for [i]X[/i] d10 dice vs. Target Number [i]Y[/i]. X could be any whole value, but for practical purposes, will rarely exceed 10, and more often be in the 2 to 5 range. Y can be any whole value between 1 and 10. I took a stab at it, and came up with this: [b]Avg = (Y + 1) ÷ 2)) * (Y ÷ 10) * X[/b] So, for Target Number of 10 on 4 dice, it would be 5.5 * 1 * 4, or 22 (the normal average of 4d10) For a Target Number of of 7 on 4 dice, it would be 4 * 0.7 * 4, or 11.2 So a target number of 7 will yield an average roll approximately 51% of a target number 10. Can anyone verify I'm figuring this correctly, or want to shed any deeper statistical analysis on this mechanic? [/QUOTE]
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