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<blockquote data-quote="LazarusLong42" data-source="post: 772001" data-attributes="member: 9620">More than one die type...All right, I've done some figuring, and about the best I can come up with is the following:<img src="http://www.invirtuo.cc/dice2.jpg" alt="" class="fr-fic fr-dii fr-draggable " data-size="" style="" />where n and d are the number and size of each set of dice; R is the result desired; and N is the total dice.&nbsp; So, for 3d6 + 2d4:n1 = 3d1 = 6n2 = 2d2 = 4N = 5Given this equation and the one above, I think the math-minded people in this thread can easily extrapolate for three or more types of dice.&nbsp; The only problem is how many iterations the algorithm goes for... that is, the definition of m1 and m2 in this equation.The problem is that there are three criteria:m1 &lt;= n1;m2 &lt;= n2;i*d1 + j*d2 &lt;= R - NIf one defines m1 as in the original equation, one then must find an expression for m2, in terms of n1, n2, d1, d2, R, N, and i.&nbsp; If anyone can find an expression for that, let me know.</blockquote>

[QUOTE="LazarusLong42, post: 772001, member: 9620"] [b]More than one die type...[/b] All right, I've done some figuring, and about the best I can come up with is the following: [IMG]http://www.invirtuo.cc/dice2.jpg[/IMG] where n and d are the number and size of each set of dice; R is the result desired; and N is the total dice. So, for 3d6 + 2d4: n1 = 3 d1 = 6 n2 = 2 d2 = 4 N = 5 Given this equation and the one above, I think the math-minded people in this thread can easily extrapolate for three or more types of dice. The only problem is how many iterations the algorithm goes for... that is, the definition of m1 and m2 in this equation. The problem is that there are three criteria: m1 <= n1; m2 <= n2; i*d1 + j*d2 <= R - N If one defines m1 as in the original equation, one then must find an expression for m2, in terms of n1, n2, d1, d2, R, N, and i. If anyone can find an expression for that, let me know. [/QUOTE]

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