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<blockquote data-quote="NotAYakk" data-source="post: 7907786" data-attributes="member: 72555">In 4e my rule of thumb was secondary targets where worth 50% of primary. You could probably use a harmonic sum or something instead, but 50% did a good enough job.If you deal only aoe to N targets at Y total damage, or deal perfect single taget damage, the AOE case will result in twice as much damage from the enemies before they drop.&nbsp; This is because single target damage results in a triangle of monsters alice, while aoe results in a rectangle.&nbsp; The width is the same, but the area of the triangle is half of the rectangle.If you do 1 monsters worth of single target damage per round, and there are 5 to start, you get 5+4+3+2+1 monster-rounds of atracks.If instead your total damage is the same, except it is AOE, you take 5+5+5+5+5 damage.One is a triangle of height and width 5, so area of 5*5/2.&nbsp; The other is a rectangle (well square) of area 5*5.&nbsp; So twice as much, so half as good.In reality it gets messier, but this is good enough.But this also aasumes you are a PC on the winning side.&nbsp; The DMG assumption of 2 targets is equivalent id we assume 4 PCs and 3/4 are hit by it.</blockquote>

[QUOTE="NotAYakk, post: 7907786, member: 72555"] In 4e my rule of thumb was secondary targets where worth 50% of primary. You could probably use a harmonic sum or something instead, but 50% did a good enough job. If you deal only aoe to N targets at Y total damage, or deal perfect single taget damage, the AOE case will result in twice as much damage from the enemies before they drop. This is because single target damage results in a triangle of monsters alice, while aoe results in a rectangle. The width is the same, but the area of the triangle is half of the rectangle. If you do 1 monsters worth of single target damage per round, and there are 5 to start, you get 5+4+3+2+1 monster-rounds of atracks. If instead your total damage is the same, except it is AOE, you take 5+5+5+5+5 damage. One is a triangle of height and width 5, so area of 5*5/2. The other is a rectangle (well square) of area 5*5. So twice as much, so half as good. In reality it gets messier, but this is good enough. But this also aasumes you are a PC on the winning side. The DMG assumption of 2 targets is equivalent id we assume 4 PCs and 3/4 are hit by it. [/QUOTE]

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