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<blockquote data-quote="Esker" data-source="post: 7907965" data-attributes="member: 6966824">To remove the impact of overkill, let's use an even number of monsters -- say 2M -- leaving the party damage at 2N and the AoE per target at N, and set the number of HP per monster to KN. That way, with no contribution from the caster, the party will take MK rounds to go through the monsters' 2MKN HP with no overkill damage, and with the one-time 2MN contribution from the caster they will take MK-M rounds, with none left over (regardless of whether the caster is doing single target or AoE damage).Assuming no contribution from the caster, it takes ceiling(K/2) rounds to kill the first monster, then floor(K/2) rounds to kill the second, ceiling(K/2) to kill the third, and so on, so the number of turns by each monster, as a function of the order in which they get attacked, is1.&nbsp; &nbsp; &nbsp; &nbsp; ceiling(K/2)&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp; = 0K + ceiling(K/2)2.&nbsp; &nbsp; &nbsp; &nbsp; ceiling(K/2) + floor(K/2)&nbsp; = 1K3. K + ceiling(K/2)&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 1K + ceiling(K/2)4. K + ceiling(K/2) + floor(K/2)&nbsp;&nbsp; = 2K5. 2K + ceiling(K/2)&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 2K + ceiling(K/2)6. 2K + ceiling(K/2) + floor(K/2) = 3K...for a total ofM*ceiling(K/2)+[(1-1)*K+1*K + (2-1)*K+2*K + ... + (M-1)K + MK]which simplifies to M*ceiling(K/2) + M^2 * K enemy turns.An AoE from the caster is equivalent to reducing K by 1, since we are starting out subtracting N from each monster's HP, so we wind up preventing either M^2 or M^2+1 enemy turns, depending on whether K is even or odd (respectively).</blockquote>

[QUOTE="Esker, post: 7907965, member: 6966824"] To remove the impact of overkill, let's use an even number of monsters -- say 2M -- leaving the party damage at 2N and the AoE per target at N, and set the number of HP per monster to KN. That way, with no contribution from the caster, the party will take MK rounds to go through the monsters' 2MKN HP with no overkill damage, and with the one-time 2MN contribution from the caster they will take MK-M rounds, with none left over (regardless of whether the caster is doing single target or AoE damage). Assuming no contribution from the caster, it takes ceiling(K/2) rounds to kill the first monster, then floor(K/2) rounds to kill the second, ceiling(K/2) to kill the third, and so on, so the number of turns by each monster, as a function of the order in which they get attacked, is 1. ceiling(K/2) = 0K + ceiling(K/2) 2. ceiling(K/2) + floor(K/2) = 1K 3. K + ceiling(K/2) = 1K + ceiling(K/2) 4. K + ceiling(K/2) + floor(K/2) = 2K 5. 2K + ceiling(K/2) = 2K + ceiling(K/2) 6. 2K + ceiling(K/2) + floor(K/2) = 3K ... for a total of M*ceiling(K/2)+[(1-1)*K+1*K + (2-1)*K+2*K + ... + (M-1)K + MK] which simplifies to M*ceiling(K/2) + M^2 * K enemy turns. An AoE from the caster is equivalent to reducing K by 1, since we are starting out subtracting N from each monster's HP, so we wind up preventing either M^2 or M^2+1 enemy turns, depending on whether K is even or odd (respectively). [/QUOTE]

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