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Quick dice probability question
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<blockquote data-quote="Puggins" data-source="post: 5103509" data-attributes="member: 12386"><p>the difference that dedekind alluded to is that the two-roll method is non-linear. The 6% difference is at 15+ is not the largest difference- the largest is at 10. </p><p></p><p>Only 25% of all results of the two-roll method are 10 or less, whereas 35% of d20+3 are 10 or less. Either method makes a "below average" roll (10 or less on a plain-jane d20 roll) less likely, but the two-roll method produces such a result almost 30% less often. If you as a player prefer to roll as few "poor" rolls as possible, the two-roll wins by a reasonable margin. It's the same reason why the Avenger's class feature is worth more than a +3, especially against anything except soldiers.</p><p></p><p>Honestly, though, I think either one works perfectly well so longer as you have no critical failure or success house rule effects.</p></blockquote><p></p>
[QUOTE="Puggins, post: 5103509, member: 12386"] the difference that dedekind alluded to is that the two-roll method is non-linear. The 6% difference is at 15+ is not the largest difference- the largest is at 10. Only 25% of all results of the two-roll method are 10 or less, whereas 35% of d20+3 are 10 or less. Either method makes a "below average" roll (10 or less on a plain-jane d20 roll) less likely, but the two-roll method produces such a result almost 30% less often. If you as a player prefer to roll as few "poor" rolls as possible, the two-roll wins by a reasonable margin. It's the same reason why the Avenger's class feature is worth more than a +3, especially against anything except soldiers. Honestly, though, I think either one works perfectly well so longer as you have no critical failure or success house rule effects. [/QUOTE]
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