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<blockquote data-quote="Herremann the Wise" data-source="post: 877982" data-attributes="member: 11300">You have 12 balls, one of which is heavier.Split into two groups of 6. One will be heavier and this will have the weighted ball so you then:Split that group of six into two groups of three. Again you take the set of balls in it that's heavier.You are now left with three balls one of which is weighted and you have one use of the scales left.Pick any two out of the three balls and put them on the scales. If one of them is heavier, you know that's the weighted ball. If the scales balance, then you know it must be the ball that was left out.[Edit: Ha. Ignore the above, I fell for the same thing! <img src="https://cdn.jsdelivr.net/joypixels/assets/8.0/png/unicode/64/1f609.png" class="smilie smilie--emoji" loading="lazy" width="64" height="64" alt=";)" title="Wink&nbsp; &nbsp; ;)"&nbsp; data-smilie="2"data-shortname=";)" /> )Best RegardsHerremann the WisePS:Good stuff RangerWickett. Unfortunately, most people miss out on the hidden fourth clue - that the sum is ambiguous. Its a good not too easy, not too difficult puzzle. (And apologies for the writing, my skill in prose far outweighs my skill in poetry <img src="https://cdn.jsdelivr.net/joypixels/assets/8.0/png/unicode/64/1f609.png" class="smilie smilie--emoji" loading="lazy" width="64" height="64" alt=";)" title="Wink&nbsp; &nbsp; ;)"&nbsp; data-smilie="2"data-shortname=";)" /> ).</blockquote>

[QUOTE="Herremann the Wise, post: 877982, member: 11300"] You have 12 balls, one of which is heavier. Split into two groups of 6. One will be heavier and this will have the weighted ball so you then: Split that group of six into two groups of three. Again you take the set of balls in it that's heavier. You are now left with three balls one of which is weighted and you have one use of the scales left. Pick any two out of the three balls and put them on the scales. If one of them is heavier, you know that's the weighted ball. If the scales balance, then you know it must be the ball that was left out. [Edit: Ha. Ignore the above, I fell for the same thing! ;) ) Best Regards Herremann the Wise PS: Good stuff RangerWickett. Unfortunately, most people miss out on the hidden fourth clue - that the sum is ambiguous. Its a good not too easy, not too difficult puzzle. (And apologies for the writing, my skill in prose far outweighs my skill in poetry ;) ). [/QUOTE]

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