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<blockquote data-quote="AeroDm" data-source="post: 1876892" data-attributes="member: 13650">Ignore me if I am not understanding what you are saying, but it seems that you are implying your 20 sided die has a higher chance of landing on an 11 than on a 12, a 12 than a 13, and so on.&nbsp; Simple rational thought shows that this cannot be.&nbsp; Every number _should_ come up 5% of the time.A d100 has an equal chance of producing any number between 1 and 100. The fact that significant treasure items are placed at the ends is simply because the ends are more significant than the middle.&nbsp; Contrived, eh?2d10 skews the results closer to 11 because of the total set of outcomes it can have.&nbsp; While each die is still equally likely to come up with any number 1-10, of the 100 possible combinations only one equals 20 (two 10's) while ten combinations equal 11 (1,10..2,9..3,8..4,7..5,6..and their opposites).&nbsp; Hence you are 10 times more likely to get a result of 11 than you are of 20.</blockquote>

[QUOTE="AeroDm, post: 1876892, member: 13650"] Ignore me if I am not understanding what you are saying, but it seems that you are implying your 20 sided die has a higher chance of landing on an 11 than on a 12, a 12 than a 13, and so on. Simple rational thought shows that this cannot be. Every number _should_ come up 5% of the time. A d100 has an equal chance of producing any number between 1 and 100. The fact that significant treasure items are placed at the ends is simply because the ends are more significant than the middle. Contrived, eh? 2d10 skews the results closer to 11 because of the total set of outcomes it can have. While each die is still equally likely to come up with any number 1-10, of the 100 possible combinations only one equals 20 (two 10's) while ten combinations equal 11 (1,10..2,9..3,8..4,7..5,6..and their opposites). Hence you are 10 times more likely to get a result of 11 than you are of 20. [/QUOTE]

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