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<blockquote data-quote="Nonlethal Force" data-source="post: 3391864" data-attributes="member: 35788">Simple: the OP asked it to matter.&nbsp; The original post admits that rule zero always applies, but intentionally asked for dialogue that assumed it did matter!Given that volume is a function of radius cubed, it depends on what the OP meant by half as small.&nbsp; If half meant half the radius, then this point is probably significantly important!If the OP mean half volume, then the radius would only be smaller by a factor of the cube root of two.&nbsp; That's much less significant.[Sblock=Example]To give an example, say I have a globe with a 3 foot radius.&nbsp; V = (4/3)(pi)(r^3).&nbsp; So, V = (4/3)(pi)(27), or V = 36(pi).To backward engineer the desired radius, a globe with half the volume would have volume of 18(pi).&nbsp; So ...18(pi) = (4/3)(pi)(r^3).&nbsp; Dividing both sides by pi gives 18 = (4/3)(r^3).&nbsp; Multiplying both sides by (3/4) gives ... (27/2) = r^3.&nbsp; In other words, r = 3/[(2^(1/3)].&nbsp; r ~ 2.4.That would probably not be a very noticable difference for the typical observer on the planet.[/Sblock]</blockquote>

[QUOTE="Nonlethal Force, post: 3391864, member: 35788"] Simple: the OP asked it to matter. The original post admits that rule zero always applies, but intentionally asked for dialogue that assumed it did matter! Given that volume is a function of radius cubed, it depends on what the OP meant by half as small. If half meant half the radius, then this point is probably significantly important! If the OP mean half volume, then the radius would only be smaller by a factor of the cube root of two. That's much less significant. [Sblock=Example]To give an example, say I have a globe with a [U]3 foot radius[/U]. V = (4/3)(pi)(r^3). So, V = (4/3)(pi)(27), or [B]V = 36(pi)[/B]. To backward engineer the desired radius, a globe with half the volume would have volume of 18(pi). So ... 18(pi) = (4/3)(pi)(r^3). Dividing both sides by pi gives 18 = (4/3)(r^3). Multiplying both sides by (3/4) gives ... (27/2) = r^3. In other words, r = 3/[(2^(1/3)]. [U]r ~ 2.4[/U]. That would probably not be a very noticable difference for the typical observer on the planet.[/Sblock] [/QUOTE]

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