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So, about this math problem...
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<blockquote data-quote="LazarusLong42" data-source="post: 1206321" data-attributes="member: 9620"><p>Ay ay ay. For any complex network of more than a few rooms, you're no longer talking about a simple statistics problem; you're talking about chaos theory. However, for some simple networks we should be able to figure out actual formulas.</p><p></p><p>The easiest is a ring of N rooms, connected 0-1-2-3-4-.... with the last room connected back to room 0. As t approaches infinity: if N is odd, the probability is 1/N for all rooms; if N is even, the probability is 2/N for odd rooms at odd time increments, 0 for even rooms at odd time increments, and vice versa for even time increments.</p><p></p><p>(This is assuming the N rooms are labeled 0, 1,... , N-1 and that the dragon starts at t=0 in room 0.)</p><p></p><p>The simple case here--that the probability is simply 1/N for each room--would also be the case for any system in which every room was connected to every other--for instance, the room placed on the corners of a tetrahedron with tunnels along the edges, or, assuming tunnels can cross and not create "rooms", a pentagram.</p><p></p><p><strong>The Sigil</strong> has already answered for your network. It's actually pretty easy to set up in Excel and run out for a hundred iterations or so.</p><p></p><p>And now, you have me setting up random ones because, yes, I'm a dork... <img src="https://cdn.jsdelivr.net/joypixels/assets/8.0/png/unicode/64/1f642.png" class="smilie smilie--emoji" loading="lazy" width="64" height="64" alt=":)" title="Smile :)" data-smilie="1"data-shortname=":)" /></p></blockquote><p></p>
[QUOTE="LazarusLong42, post: 1206321, member: 9620"] Ay ay ay. For any complex network of more than a few rooms, you're no longer talking about a simple statistics problem; you're talking about chaos theory. However, for some simple networks we should be able to figure out actual formulas. The easiest is a ring of N rooms, connected 0-1-2-3-4-.... with the last room connected back to room 0. As t approaches infinity: if N is odd, the probability is 1/N for all rooms; if N is even, the probability is 2/N for odd rooms at odd time increments, 0 for even rooms at odd time increments, and vice versa for even time increments. (This is assuming the N rooms are labeled 0, 1,... , N-1 and that the dragon starts at t=0 in room 0.) The simple case here--that the probability is simply 1/N for each room--would also be the case for any system in which every room was connected to every other--for instance, the room placed on the corners of a tetrahedron with tunnels along the edges, or, assuming tunnels can cross and not create "rooms", a pentagram. [b]The Sigil[/b] has already answered for your network. It's actually pretty easy to set up in Excel and run out for a hundred iterations or so. And now, you have me setting up random ones because, yes, I'm a dork... :) [/QUOTE]
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So, about this math problem...
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