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Message: <blockquote data-quote="Patryn of Elvenshae" data-source="post: 5705360" data-attributes="member: 23094">No, it doesn't.  It really, really doesn't.  The fact that you believe this is why you are wrong.Nowhere does it say that you are actually treated as rolling anything - until the end, at which point you calculate your result as if you had rolled a 20.Halfway through, you haven't rolled anything - you are treated as having failed 10 times, but there's no assumed number rolled on the die.  That's why, if you Take 20 on something which you could succeed at on a roll of a 1, you still take 20 times as long to accomplish it.It's not a disconnect.  It's the rules - because there is no rolling.Yes, you absolutely do, which is why the rules say:So for a 1-standard-action action, when you take 20, you fail for 19 rounds (regardless of the die value needed to succeed) and on the 20th, you get a result as if you had rolled a 20 (which may, also, be a failure).EDIT:Consider someone breaking down a door, Taking 20 on the Strength check.  In round 1, he takes the "Break down the door" standard action.  Did he succeed at breaking down the door?  No - the door is obviously still standing.  He has, therefore, failed to break down the door in round 1.  This continues for 18 further rounds.  Then, in round 20, we check whether or not a 20 + Strength mod is enough to break down the door - thus, success becomes possible only in the 20th round.  This is true even if the door's break DC is 5 and he's got a Strength bonus of +4 (and could auto-succeed if he just rolled).  In rounds 1-19, even though any roll of the die would result in a success, he fails to break down the door.</blockquote>

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