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The Quadratic Problem—Speculations on 4e
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<blockquote data-quote="Cheiromancer" data-source="post: 3752422" data-attributes="member: 141"><p>That's exactly the problem with the AC and attack numbers; they are nowhere near as easy to manage as the hit points and damage.</p><p></p><p></p><p></p><p>And even hit points and damage are not as simple as one would like. <img src="https://cdn.jsdelivr.net/joypixels/assets/8.0/png/unicode/64/1f642.png" class="smilie smilie--emoji" loading="lazy" width="64" height="64" alt=":)" title="Smile :)" data-smilie="1"data-shortname=":)" /> These calculations are all rough calculations, giving the general scheme of things.</p><p></p><p></p><p></p><p>I start with a different set of assumptions. I'm assuming that when they find a monster that is a moderate challenge (25% resources) against four Nth-level PCs, they say it is a MonN. (Thanks for the improved notation, btw).</p><p></p><p>Now given Lanchester's Square Law, that means that a MonN is 4 times as powerful as a single PCN. Which means that it is the same power as a PC(N+2) - assuming the exponential law follows for PCs as well as monsters. Which is the assumption in 3.5.</p><p></p><p>An alternative way of saying the same thing is that the CR of PCN is N-2. Which means that a single Mon5 would be a cointoss against a PC7, and would use up 25% of the resources of a PC9. On average, that is: not all characters are equally capable against all challenges.</p></blockquote><p></p>
[QUOTE="Cheiromancer, post: 3752422, member: 141"] That's exactly the problem with the AC and attack numbers; they are nowhere near as easy to manage as the hit points and damage. And even hit points and damage are not as simple as one would like. :) These calculations are all rough calculations, giving the general scheme of things. I start with a different set of assumptions. I'm assuming that when they find a monster that is a moderate challenge (25% resources) against four Nth-level PCs, they say it is a MonN. (Thanks for the improved notation, btw). Now given Lanchester's Square Law, that means that a MonN is 4 times as powerful as a single PCN. Which means that it is the same power as a PC(N+2) - assuming the exponential law follows for PCs as well as monsters. Which is the assumption in 3.5. An alternative way of saying the same thing is that the CR of PCN is N-2. Which means that a single Mon5 would be a cointoss against a PC7, and would use up 25% of the resources of a PC9. On average, that is: not all characters are equally capable against all challenges. [/QUOTE]
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